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All of these compounds contain polar C-Cl bonds but the tetrahedral arrangement makes the bond dipoles to cancel each other and thus the dipole moment actually decreaces with increasing number of Cl atoms:

CH3Cl (1.87D) >CH2Cl2 (1.54D)> CHCl3 (1.02 D) > CCl4, CH4 (0 D)

You should check:
http://dwb.unl.edu/Teacher/NSF/C06/C06Links/www.uis.edu/7Etrammell/organic/introduction/polarity.htm

2006-07-05 06:12:39 · answer #1 · answered by bellerophon 6 · 1 0

CHCl3 would have the greatest dipole moment. The atoms are in a tetrahedron with the Carbon in the center. The negativity of the Clorine is what creates the dipole and three of them create a greater net force.

2006-07-05 05:36:06 · answer #2 · answered by The Mog 3 · 0 1

Ch3cl Dipole Moment

2016-11-10 22:34:46 · answer #3 · answered by ustico 4 · 0 0

bellerophon nailed the answer on this one.

The problem is that the affect of adding more electronegative atoms is not always additive. Dipole moments are vector quantities, so the two distortions of the electron cloud from the 2 or 3 carbons are countered by the distortions of another. The net effect is what's important, not the affect of each atom.

2006-07-05 09:53:40 · answer #4 · answered by niuchemist 6 · 0 0

CH3Cl has a greater dipole moment, because the CH3- is a stronger electron donor than CH2- and CH-

2006-07-07 21:16:16 · answer #5 · answered by Anonymous · 0 0

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All the above compounds are tetrahedral in shape. Since the dipole moment of a bond is aligned parallel to that bond, we have a tetrahedron of dipoles. If all the dipoles are equal, they will cancel out if arranged tetrahedrally, that happens in CCl4, it has a 0 dipole moment.

2016-04-03 01:35:35 · answer #6 · answered by Anonymous · 0 0

CH2Cl2 depending on arrangement

2006-07-05 05:36:33 · answer #7 · answered by shiara_blade 6 · 0 1

CHCL3 is the right answer

2006-07-05 06:14:14 · answer #8 · answered by qwine2000 5 · 0 0

i think CH2Cl2 does

2006-07-05 05:38:50 · answer #9 · answered by Anonymous · 0 0

CH3-Cl

2006-07-05 05:38:07 · answer #10 · answered by BigD 6 · 0 0

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