Lim -> ½+ sqrt(2x-1)
...
Lim -> 6- Abs(3x-18)/6-x
...
Lim-> pi/2 sin x/x
2006-07-05 04:42:09 · 8 answers · asked by c2pre 2 in Science & Mathematics ➔ Mathematics
no limits
2006-07-05 04:46:25 · answer #1 · answered by harsha_rao s 1 · 0⤊ 0⤋
The first one is zero clearly because the square root of smaller and smaller numbers that approach zero will also be approaching zero.
The second one is equivalent to the limit of (18-3x)/(6-x) since Abs(3x-18) is equal to 18-3x if x<6. Thus, you divide the two pieces to get the limit of 3 as x approaches 6. The answer is, therefore, 3.
I am assuming the third one is (sinx)/x and not sin(x/x), which is just sin1. Therefore, the third one is 2/pi. This is clear because sinx approaches one from both sides as the angle nears pi/2. Thus, one over pi/2 is your answer and this reduces nicely to 2/pi.
2006-07-05 12:00:48 · answer #2 · answered by itsverystrange 2 · 0⤊ 0⤋
what r u doing?
I'm not even in high school yet i know what it means!
limits r values which do not work in that particular equation.
in calculus, sometimes u use these limits to Find other things.
2006-07-05 11:58:40 · answer #3 · answered by gregjo13 2 · 0⤊ 0⤋
Well to find the limits, dood, you have to tell us where x goes to.
like
Lim (X -> 0) { sinX / X} = 1
2006-07-05 11:53:40 · answer #4 · answered by Tharaka D 2 · 0⤊ 0⤋
this is not proper question forst write the equation in right form and then ask again!!!!
2006-07-05 12:35:03 · answer #5 · answered by Parth 3 · 0⤊ 0⤋
Here we go, doing someone's math homework again...
2006-07-05 14:42:07 · answer #6 · answered by Christopher S 2 · 0⤊ 0⤋
limit must tent to something.
example:
x-->2
try to correct your questions.
2006-07-05 12:19:48 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋
you can do it.
2006-07-05 11:54:47 · answer #8 · answered by enggkid 2 · 0⤊ 0⤋