if two objects are dropped at the same time, would they land at the same time if they have the same air resistance but different weight? for example, a bottle of mile and an empty bottle.
2006-07-03 08:55:28 · 22 answers · asked by jonathanmusty 2 in Science & Mathematics ➔ Other - Science
no
2006-07-03 08:58:01 · answer #1 · answered by jaybirdladybug 2 · 0⤊ 0⤋
If there is no air resistance then they would land at the same time. If they are the same shape (hence same air resistance) then the denser (heavier) object will land first.
For this kind of thing you have to consider the forces on the object.
The force from air resistance increases with speed and size and slows things down.
The force from gravity only depends on mass. As things fall faster the air resistance increases but the gravitational force stays the same, eventually the two are the same and the object stops accelerating. More massive objects have more gravitational force so need more speed for this to be balanced and so they fall faster.
2006-07-03 11:46:58 · answer #2 · answered by m.paley 3 · 0⤊ 0⤋
They would land together. The acceleration due to gravity is independant of mass (or weight). The only thing that makes a feather fall slower than an apple is air resistance. In a vacuum they would fall at the same speed and reach the ground together.
2006-07-03 10:13:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
good question.
air resistance stops an object from accelerating when it reaches a certain velocity it does not slow the object down unless u increase the resistance like a parashoot.
the hevier bottle will accelerate faster but both bottles if having the same air resistance will settle at the same velocity.
but due to the hevier bottle reaching the max velocity faster it will hit the ground first.
sorry my mistake i was wrong they would accelerate at the same speed and therefore hit the ground the same time
2006-07-03 09:02:05 · answer #4 · answered by kevin h 3 · 0⤊ 0⤋
Yes, because the equation for distance traveled is
Xfinal-Xinitial=Initial Velocity * Time+ .5*Acceleration*Time
Your initial velocity is zero if it is being dropped. Acceleration is always constant 9.81m/(s^2) or 32.2 ft/(s^2) due to gravity, and gravity is a constant. Therefore with the same distance being traveled and a constant acceleration, it would force the time to also be equal between the two objects, so long as the air resistance is the same.
2006-07-03 09:06:31 · answer #5 · answered by ChrisRiedel_1 2 · 0⤊ 0⤋
First of all, your example doesn't match the question, in order to have the same air resistnace they'd need the same density and shape, however if you were to drop two shafts of wood, one a foot long and one 2 feet long, both 2 inches in diameter and shaped like a cylinder, and both somehow traveled point down the whole way, they would indeed strike simultaneously.
2006-07-03 09:01:01 · answer #6 · answered by Archangel 4 · 0⤊ 0⤋
Yes they would land at the same time, in a vacum being a perfect situation. On earth there would be a little time difference due to wind etc. Read any school website on gravity.
2006-07-03 08:59:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
yes they'd land at the same time. gravity would bring them down together, no matter what the weight. as long as the air resistance, doesn't play a part.
2006-07-03 08:59:55 · answer #8 · answered by rus 1 · 0⤊ 0⤋
no the full bottle will hit the ground first however if you go on the moon, and you do the same thing, they will both land at the same time!!!
2006-07-03 09:37:56 · answer #9 · answered by Cutey McPretty 3 · 0⤊ 0⤋
no the bottle of mile would dropped faster than the empty bottle because it has weight in it that makes it go faster.
2006-07-03 08:59:19 · answer #10 · answered by Anonymous · 0⤊ 0⤋
Yes they would because the acceleration due to gravity is the same for both bottles irrespective of their mass.
2006-07-04 01:55:02 · answer #11 · answered by oapboba 2 · 0⤊ 0⤋