If A and B are members of a group under the operation +, then by definition, there will always be an identity element, I, in that group with the property I + A = A = A + I for every element of the group.
The integers, rational numbers, real numbers, and complex numbers are all groups under addition, so they all have an identity member, namely 0.
Vector spaces are also groups under addition as are matrices (a subset of vector spaces) so they also have additive identities -- the zero vector and the zero matrix.
2006-07-03 08:47:47
·
answer #1
·
answered by rt11guru 6
·
2⤊
0⤋
A=0
2006-07-03 07:55:08
·
answer #2
·
answered by Goddess T 6
·
0⤊
0⤋
A=0 B=4
a+b=4
2006-07-03 07:55:15
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
If A=0, then A + B = B.
2006-07-03 07:55:46
·
answer #4
·
answered by Richard I 1
·
0⤊
0⤋
this statement will only be true if A = 0, and there are some possibilities for a to be zero :
the first, A = cos 90 degree or sin 180 degree
or, A = 1/infinity
and B is B
2006-07-04 04:11:40
·
answer #5
·
answered by momiji 1
·
0⤊
0⤋
Only A=0 would work. If this happpend though it would just be easier to say B. To get other possibilities for A instead of 0, you would need variables like 6 + -2 (4)=-2.
2006-07-03 09:15:53
·
answer #6
·
answered by wingnut3.1415 2
·
0⤊
0⤋
If A == 0 then A + B == 0 + B == B.
If B == infinity then A + B == A + infinity == infinity == B.
Otherwise, we're talking about higher level
math concepts like vectors, matrices, and additive identities.
2006-07-03 08:59:06
·
answer #7
·
answered by David Y 5
·
0⤊
0⤋
If A = 0 then A + B would still be equal to B; other than that i cannot see how it is possible.
2006-07-03 07:54:57
·
answer #8
·
answered by sam_keane_uk 3
·
0⤊
0⤋
If A=0, then whatever B=, A+B will always =0
2006-07-03 07:56:18
·
answer #9
·
answered by CleverGal 3
·
0⤊
0⤋
Not an impossibility at all. If A = 0, your equation will be true.
2006-07-03 08:07:40
·
answer #10
·
answered by mcmurrayjamiefan 4
·
0⤊
0⤋