2006-07-02 15:24:01 · 8 answers · asked by marcella i 1 in Science & Mathematics ➔ Mathematics
2x^2 + 3x = 9
Get everything on the same side
2x^2 + 3x - 9 = 0
Now factor
We know that the 2 x^2 has to be 2x and 1 x (only possible factors)
the -9 will have one positive and one negative factor
Only possible combinations are 1 and 9 or 3 and 3
Think about the combinations with the 2 and 1 and we can see that the 1 and 9 won't work, so
(2x - 3)(x+3) = 0
Set each term equal to zero and solve
2x-3 = 0 and x + 3 = 0
x = 3/2 and x = -3
2006-07-02 15:31:54 · answer #1 · answered by quietfive 5 · 0⤊ 0⤋
2x2=2+3=5
2x2=2+3x = 12
2006-07-02 15:34:29 · answer #2 · answered by ram 2 · 0⤊ 0⤋
x= 5/3
2006-07-02 15:26:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3x=9-4
3x devided by 3 and 5 devidedby 3
x=1 2/3
2006-07-02 15:42:50 · answer #4 · answered by Elwood 4 · 0⤊ 0⤋
2x^2 + 3x = 9
divide everything by 2
x^2 + (3/2)x = (9/2)
find half of (3/2), square it, add to both sides
x^2 + (3/2)x + (9/16) = (81/16)
factor left side into a perfect square
(x + (3/4))^2 = (81/16)
sqrt both sides
x + (3/4) = ±(9/4)
x = (-3/4) ± (9/4)
x = (-12/4) or (6/4)
x = -3 or (3/2)
ANS : -3 or (3/2)
2006-07-02 17:01:38 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
Its 5/3.
2X2+3x=9...
4+3x=9...
3x=9-4...
3x=5...
x=5/3
there ya go.
2006-07-02 15:35:29 · answer #6 · answered by govnasteven 2 · 0⤊ 0⤋
foil each one out until you get an answer that matches 2x2 + 9x + 9 first, outter, inner, last. try to do that.
2016-03-27 01:50:51 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Refer to my answers to your previous 3 questions.. I would not help to list everything for you.. This time round, I will only provide you the final answers so that you can double check ur answers, alright?
x = 3/2 or x = -3
Note: Use either one of the methods that I have taught you..
Cheers... (",)
2006-07-02 15:33:57 · answer #8 · answered by Ellusive Lady 3 · 0⤊ 0⤋