how fast would de earth have to spin if it has to rip itself in two (due to centrifugal forces)?

Answer 1

Centrifugal acceleration is V^2/R. R is about 4,000 miles for Earth, so if it rotated at about 38,000 MPH (at the equator), that would be fast enough to overcome gravity. In other words, objects at the equator would be weightless. Any faster and objects would be thrown off the Earth (at the equator). This is about 1/40 RPM. Loose things like people, soil and water would fly off at just a little faster speed, but I don't know how much faster would be needed to make the rocky parts fly apart. Not much faster I think, much less than double that. So lest us say somewhere between 1/40 and 1/20 RPM, or 38,000 - 76,000 MPH.

Answer 2

wait wait wait if it had more centrifugal force then it would need for to keep it with in orbit thx to agints suns' gravity then it will no longer have to stay in the orbit meaning then there wount be needing centrifugal force because now earths' speed is faster enough to leave the orbit because it is now faster then the gravity of the sun. now that earths' speed is stronger then the suns' gravity it will go strait meaning it wont be using centrifugal force :
earth will now go straight in the choosen direction where it was too strong for suns' gravity .


cintrifugal force mean- when a planet or meteor is coming in certain speed and then meets a planet or sun and orbits it because of inertia and gravity of sun or planet

inertia- speed of the moon, planet ,meteor or of a moving object in space

Answer 3

It would not be ripped in two pieces, but rather thousands. And that sort of thing can't happen.

Answer 4

why? do you want the earth to rip in half and die?

Answer 5

We be dead from gravity before it happen, so who cares.

Answer 6

good question, give yourself 10 points

Answer 7

Let's say about 1,000,000,000,000,000,000,000,000,000,000,000,000,000.000000000111111
Mile per hour

Answer 8

600rpm`s