need help c2-7c=12?

Answer 1

x = 7 + sqrt ( 97)/ 2

x = 7 - sqr t ( 97) / 2

sam ;)

Answer 2

If by this you meant

c^2 - 7c + 12
(x - 4)(x - 3)
x = 4 or 3

but if not, then

c^2 - 7c = 12
c^2 - 7c + (49/4) = (97/4)
(c - (7/2))^2 = (97/4)
c - (7/2) = ±(1/2)sqrt(97)
x = (7/2) ± (1/2)sqrt(97)

Answer 3

c^2 - 7c = 12
c^2 - 7c - 12 = 0

[-(-7) +/- sqrt((-7)^2 - 4(1)(-12)]/2(1) = c
[7 +/- sqrt(97)]/2 = c

I'm guessing you wrote this problem incorrectly and the answer should be...

[7 +/- 1]/2 = c
c = 4 or c = 3

Note, the first person who answered doesn't know the quadratic formula.

It's

[ -b +/- sqrt(b^2 - 4ac) ] / 2a

He wrote it as:

[ -b +/- sqrt(b^2 - 4a(-c)) ] / 2a

Answer 4

c2 is square, right? you should write c^2 then.

c2-7c=12
c2-7c-12=0

c= (7 +/- sqrt(7^2-4*12) ) / 2
=(7 +/- sqrt(49-48) ) / 2
={3,4}

i.e. both c=3 and c=4 are answers

Answer 5

361

Answer 6

-5c=12
c=-12/5
c=-2 and 2/5