As in..if you have 99 wins and 63 loses then what is your winning % like the Boston Red Sox right know have 49 wins and 29 loses their winning % is 628. how do u get that?
2006-07-02 06:42:39 · 8 answers · asked by Sports Dude 1 in Sports ➔ Baseball
didn't you already ask that?
2006-07-02 06:55:06 · answer #1 · answered by angela_adduci 2 · 0⤊ 0⤋
That's not exactly a percentage, it's a permillage. All you have to do is sum up the wins and the losses to get the total games number (49 + 29 = 78). Then, divide 49 by 78 and you get 0,628205... The maximum value you can obtain is 1 (if you win every single game you play). Mutiply the value by 1000 to get the 628 you referred.
If you have 99 wins and 63 losses you have played 162 games. Winning 99 you get [(99 ÷ 162) x 1000] = 0,6111111111... x 1000 â 611
2006-07-02 13:45:36 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The simplest way is to divide wins, in your example 99 by the total number of games played, 99 + 63=162 and the result is your winning percentage. 99/162 =.61111111111 or .611 .
2006-07-02 15:57:11 · answer #3 · answered by Rick H 4 · 0⤊ 0⤋
Divide the number of wins by the number of games played, and there you are.
2006-07-02 13:46:09 · answer #4 · answered by wmp55 6 · 0⤊ 0⤋
If you want a winning percentage of a MLB team, go to mbl.com.
2006-07-02 14:08:58 · answer #5 · answered by K-Deeznuts 4 · 0⤊ 0⤋
divide the wins by the total you moron
2006-07-07 12:47:56 · answer #6 · answered by Topher 5 · 0⤊ 0⤋
take ur losses and divide them by ur wins.
2006-07-02 14:00:15 · answer #7 · answered by osu_fan_82 1 · 0⤊ 0⤋
oh my god are you kidding me? STAY IN SCHOOL!
2006-07-07 04:20:21 · answer #8 · answered by Southie9 5 · 0⤊ 0⤋