2006-07-02 00:38:16 · 12 answers · asked by punno 2 in Science & Mathematics ➔ Mathematics
Zero
2006-07-02 00:46:05 · answer #1 · answered by Anonymous · 0⤊ 1⤋
There is no defined value for x....or the question is wrong. Following proper algebraic calculations:
8(2x-4)=16x
2x-4=2x
2x-2x=4
0=4
or
2x-4=2x
-4=2x-2x
-4=0
2006-07-02 09:01:50 · answer #2 · answered by ucenigma 3 · 0⤊ 0⤋
8(2x-4)=16x
16x-32=16x
-32=16x-16x
-32=0
Only thing proved is the question is wrong.
2006-07-02 08:08:03 · answer #3 · answered by jewelking_2000 5 · 0⤊ 0⤋
mhmm ? .... 8(2x-4)=16x
open the brackets.... 16x-32=16x
=16x-16x=32
therefore ans is zero? am i rite
2006-07-02 07:43:33 · answer #4 · answered by Shamur 1 · 0⤊ 0⤋
check your equation again, it doesn't make sense at least to me,
16X - 16X = 32 ----> 0 = 32 (???). there is probably no answer, and i should like to think there is a mistake somewhere.
2006-07-02 11:19:39 · answer #5 · answered by Yue C 1 · 0⤊ 0⤋
16X-32=16X
-32=0
So the answer is X is undefined or question is wrong
2006-07-02 08:11:08 · answer #6 · answered by gotit 2 · 0⤊ 0⤋
8(2x-4)=16x
16X-32=16X
16X-16X=-32 (take out '-' frm both d sides)
16X+16X=32
32X=32
X=32/32
X=1
2006-07-02 10:03:11 · answer #7 · answered by koolgrl87 3 · 0⤊ 0⤋
As jewelking indicates, there doesn't exist any value of x for which the equation is true.
2006-07-02 08:12:49 · answer #8 · answered by Michel_le_Logique 4 · 0⤊ 0⤋
undefined...zero probably..check ur ques.
2006-07-02 07:54:24 · answer #9 · answered by mysterious 2 · 0⤊ 0⤋
this question has an erroe
2006-07-02 09:22:56 · answer #10 · answered by Anonymous · 0⤊ 0⤋