well i am lost havnt done this stuff for a while
(2x^2-9x+9) divided by (X-3)
2006-06-30 17:38:13 · 4 answers · asked by investing1987 3 in Education & Reference ➔ Homework Help
it didnt help
2006-06-30 17:44:41 · update #1
divided by (X-3)
Let's work with (2x^2-9x+9) first
2X^2-9X+9
= (x^2-6x+9)+(x^2-3x)
= (x-3)^2 + x(x-3)
= (x-3) [(x-3) + x)]
=(x-3) (2x-3)
now divide that for (x-3)
(x-3) (2x-3)
---------------
(x-3)
= 2x-3 (this is your answer)
Good luck!
2006-06-30 18:01:22 · answer #1 · answered by lab_rat06 3 · 1⤊ 0⤋
it's very simple
first factorize the numerator means
2x^2-9x+9= 2x^2-6x-3x+9
= 2x(x-3)-3(x-3)
= (2x-3)(x-3) -------------------- 1
now divide the facorize equation number 1 with the denominator means:
(2x-3)(x-3)/x-3
cancel the numerator x-3 with denominator x-3
so, the answer is ==== (2x-3)
2006-07-01 00:49:53 · answer #2 · answered by priya b 2 · 0⤊ 0⤋
use the web site
2006-07-01 00:42:08 · answer #3 · answered by kuldipsinghsra 1 · 0⤊ 0⤋
= 2x + 15 remainder: 54 ... haha your welcome
2006-07-01 00:45:26 · answer #4 · answered by LoveLiveLife 1 · 0⤊ 0⤋