does anybody know the application of the hardy-weinberg equation?

Question

it is all about genetics........................

Answer 1

Well, the equation is : (p^2) + (2pq)+(q^2)= 1....where (p^2) and (q^2) represent the frequency of homozygous alleles and (pq+qp=2pq) represent the frequency of heterozygous alleles.

The way to use this formula is for example : " if you have a plant population that consists of 84% plants with Red flowers (RR, Rr -alleles) and 16% White flowers ( rr-alleles)," you use the formula above as follows:

(q^2) = .16= White flowered plants (rr trait)
(p^2)+ (2pq)= .84= Red flowered plants (RR, or Rr traits)



Now there is another equation : p+q=1

So, take the square root of (q^2)=.16, q=.4 and then plug that into p+q=1. Now solve for p, p should be .6. Now note that q=.4 and p=.6 and with that said plug it into the original equation in order to find the frequency.

(p^2) +(2pq)+(q^2)=1

(p^2) = (.6) (.6) = .36 or 36% for the homozygous dominant trait (RR)

(q^2)= (.4)(.4)= .16 or 16% for the homozygous recessive trait- (rr)

(2pq) = (2)(.6)(.4)= .48 or 48% for the heterozygous trait - (Rr).

All of this should equall 100%. So 36%+16%+48%=100%.

So, basically the Hardy-Weinberg equation is to see the frequency of the alleles (RR,Rr, and rr) in a population.

Answer 2

It tells you if evolution has occurred over a generation. If the protons have changed then evolution has occurred. It deals with the number of alleles that are carried on from one generation to the next. Only the beneficial alleles will be passed on.

Answer 3

p^2+2pq+q^2=1

Answer 4

Is a population stable or changing..........?