divide x^4+x^2-80/x+3.....please help........?

Answer 1

x^3-3x^2+10x-30 R 10
it's x+3 / x^4+0x^3+x^2+0x-80
x^4+3x^3
-------------
-3x^3+x^2
-3x^3-9x^2
-------------
10x^2+0x
10x^2+30x
--------------
-30x-80
-30x-90
------------
10

Answer 2

Please excuse the mess, I could not get things to line up with only spaces, so I inserted a bunch of periods. The periods are supposed to be spaces. I made a sign error earlier, but now I am certain that my answer is correct. Steve, you got it wrong too: multiply and see for yourself: x^3-3x^2+10x-20+ (-20/(x+3)) is not the quotient.

If you read carefully, I will show you the absolute easiest way of dividing polynomials. The short way to do your problem goes like this:
-3 |........1 ........ 0 ......... 1 ............. 0 ......... -80
......................... -3 ........ 9 ............ -30 ...........90
--------------------------------------------------------------------------------------------------------
.............1.......... -3..........10......... -30...... | ........10

Explanation:
First, write negative of the second part of the divisor to the left of the page. In this case, it's -3. If the leading coefficent of the x in the divisor is not 1 (i.e. (ax + b)), factor a from the divisor like (x + b/a) and divide the dividend polynomial by a.

Then, write the coefficients of the polynomial to the left of the number from the above step. Start from the number of the highest degree and proceed down to elements of degree 0 (constants). Remember to include zeros for missing elements. These coefficents comprise the entire first row.

Next, skip a line and draw a line at the bottom of the line you skipped. Copy the first coefficent to the position beneath the line in the same column (the two 1's in your problem).

Next, multiply the last number in the bottom row by the first number you wrote. To begin with in your case, it's 1 * -3 = -3.

Next, add the numbers in the column you're working in and write the result beneath the line in the same column. So, 0 + -3 = -3.

Next, multiply that last number in the bottom row by the first number in the top row and write the result in the appropriate column in the second row. So, you end up with 9 because -3 * -3 = 9. Add the column, write it down, multiply again, write, add the column, etc. When you add the last column, stop.

Now, you read your answer off the bottom row as follows:
The first number is a coefficient of a number one degree less than the original dividend. So it's degree is 3 (i.e., x^3). The one next to it has degree 2, and the one next to it has degree 1. The next one is a constant, and the last one is the remainder. So your answer is x^3 - 3x^2 + 10x - 30 R 10.

It takes only a bit of practice, but it ultimitely saves a lot of time. Good luck!

Answer 3

There are some thoughtful posts here, but I do not see the correct answer. There is an obvious syntax error with your problem. I think you are trying to solve for (x^4+x^2-80) / (x+3).
The first thing to remember is that if you are doing polynomial division, you must put both the numerator and denominator in parentheses, or else you will get an incorrect answer.Then, as a previous poster mentioned, you perform polynomial division...typically a skill learned in algebra 2. The correct final answer is:

x^3-3x^2+10x-20+ (-20/(x+3))

The answer looks messier than it should, because this type of math expression is not meant to be typed on a regular keyboard.

Answer 4

If you know how to do synthetic division, that is the easy way. Otherwise, you must do polynomial long division. Set it up the way you normally set up a long division problem with numbers using x+3 as the divisor and the polynomial as the dividend. Now see how many times x goes into x^4. Multiply this by the divisor and subtract the result form the dividend. Now see how many times x goes into x^2. Continue until you get to the last term and what you are left with is the remainder. You may want to throw in a zero x^3 and a zero x to make it easier.

Answer 5

X^3 - 3X^2 + 10X - 30 + (10/x+3)

Do the long division but insert 0x^3 and 0x to make up the missing exponents. There will be a remainder of 10.

Answer 6

I'm not sure but I'll try to help.

[x^4 + x^2 - 80] / [x+3]

= [x^3(x-3) + 3x^3 + x^2 - 80] / [x+3]

=x^3+{[3x^2(x-3) + 10x^2 - 80] / [x+3]}

= x^3 + 3x^2 +{[10x(x-3) + 30x - 80] / [x+3]}

= x^3 + 3x^2 + 10x + {30(x-3) + 10 / (x-3)}

= x^3 + 3x^2 + 10x + 30 + (10/ x-3)

Hope that helps. =D

Answer 7

Such a problem doesn't simplify any further. . . Considering the grammar of your question you have merely posted the answer.

Answer 8

i aagree with latina princess

Answer 9

no comment