How many square feet are in a round pool 18feet by 4 feet deep?

Answer 1

who cares get a real pool,,,, you just need to join the "Y"

Answer 2

the surface area will in square fee/metres, though the volume will be a cubic measurement..

i take it that the 18feet is the distance across the middle?

area = Pi x r squared;
Pi = approx 3.142, r= radius (from centre to outside, so thats 1/2 of 18 = 9.

so, r squared will be 9 x 9 = 81, x 3.142 (Pi) = ??

multiply that by 4 (depth in feet) - total volume of water, in cubic feet.

same equation works if you transfer into metres, before doing the sums. (divide feet by 3.3)

Answer 3

That question is impossible to answer because you don't know the other width or length. Depth has nothing to do with square feet. That'd be cubic feet. And in either case you're missing a part of the equation.

Answer 4

The volume of the pool is 1,018 cubic feet and the area of the bottom of the pool is 254.5 square feet. The area of the sidewall is 226 square feet.

Answer 5

If the pool's diameter is 18 feet then the area would be:

3.14 * 9 * 9 = 254.34 square feet

If you then want the volume or cubic feet just multiply that by the depth: 254.34 * 4 = 1017.36 cubic feet

Answer 6

254 sq ft - Here is a GOOD Link below -

If you want the final volume of water - I answered this allready

You have approx 7646.4 US Gallons
4x18x18x5.9= 7646.4

At a level of 3 1/2 feet (probable H20 Level) = 6690.6 gal

Answer 7

There are 254.47 square feet. (surface area)
1017 cubic feet.
And 7634 gallons of water.
which weighs 63,592 lbs.

Answer 8

It depends on how many squares are swimming in it at the time.

Answer 9

You already have a lot of good answers, but look at the website below for more information. Good luck!

Answer 10

254.5 square feet. Depth has nothing to do with area!