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2006-06-30 10:13:03 · 19 answers · asked by hact2009 2 in Education & Reference Higher Education (University +)

19 answers

365 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31536000 secs/year

For a leap year
366 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31622400 secs/year

Some would be tempted to give this answer:
365.24219907407407407407407407407 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31556926 secs/year, however a calendar year does not contain partial days. Leap years are used to make up for the missing parts of the day.

2006-06-30 10:16:51 · answer #1 · answered by davidmi711 7 · 0 0

60 x 60 x 24 x 365 = 31536000

2006-06-30 10:18:03 · answer #2 · answered by Anonymous · 0 0

31 556 926 seconds

2006-06-30 10:16:11 · answer #3 · answered by Ashley 3 · 0 0

there are 31536000 seconds in a year


60 seconds in a min * 60 min in an hour * 24 hours in a day * 365 days in a year= 31536000 seconds in a year

2006-06-30 10:22:53 · answer #4 · answered by hi 3 · 0 0

1 min = 60 Sec
1 hour= 60 min * 60 sec = 3600 sec
1 day = 24 H * 60 min * 60 sec = 86400 sec
1 year = 365 days * 24 H * 60 min * 60 sec =31536000 sec
=> 1 year = 31536000 sec

Have fun

2006-06-30 10:28:25 · answer #5 · answered by Justin cool 2 · 0 0

For a regular year, there are 31,536,000 seconds. For leap year, add another 86,400 seconds.

2006-06-30 10:18:16 · answer #6 · answered by Irish1952 7 · 0 0

365 days/year
times
24 hours/day
times
3600 seconds per hour

unless it is a leap year then you have 366 days.

2006-06-30 10:17:01 · answer #7 · answered by BonesofaTeacher 7 · 0 0

60*60*24*365=31536000

2006-06-30 10:16:19 · answer #8 · answered by ? 3 · 0 0

31,557,600 (If you're going by the Julian Calender, although I do have to note that our years are getting longer and this calculation may not be entirely correct.)

2006-06-30 10:23:28 · answer #9 · answered by Irkedmonkey 2 · 0 0

In leap year, it is
364x24x60x60=

2006-06-30 10:30:17 · answer #10 · answered by pushpam 2 · 0 0

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