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2 answers

if S = a+b and P= ab
then a and b are the roots of the equation:
f(x) = x^2 - Sx + P= 0
I assume you say algebraic over Q.
Now S,P are algebraic over Q implies that the roots of f are algebraic over Q, i.e a and b.
why? because a and b are algebraic over the field of algebraic numbers so they become algebraic too.

2006-06-30 10:24:47 · answer #1 · answered by Theta40 7 · 0 0

let
a=x+iy
b=x-iy
a+b=2x
a-b=2iy
ab=(x+iy)(x-iy)=x^2 -y^2

2006-07-07 04:19:12 · answer #2 · answered by Anonymous · 0 0

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