Please don't give me a hard time for asking for help, I have already done this problem I just want to make sure i'm on the right track\my answer is correct. Thanks in advance (those who don't scold me)
2006-06-30 04:53:57 · 9 answers · asked by j h 2 in Science & Mathematics ➔ Chemistry
depends if it is 25.9% nitrogen by molar weight or total # of atoms
2006-06-30 06:51:32 · answer #1 · answered by Anonymous · 0⤊ 2⤋
Is that a mass percent, or a molar percent, because that would change how you do the problem. Usually, empirical formula type questions give the mass percent, so I will assume that is what it is.
First, you pretend that the percentage you have is the number of grams you have of each (25.9 g of N and 74.1 g of O)
Divide each by mw
25.9/14=1.85
74.1/16=4.63
Now, divide both of those numbers by the smallest number, 1.85.
1.85/1.85=1
4.63/1.85=2.5
For the empirical formula, you can't have any fractions, so multiply both numbers by 2 and you get
N2O5
2006-06-30 05:26:27 · answer #2 · answered by q2003 4 · 1⤊ 0⤋
When trying to figure out empiricle formulas, look at the ratios of atoms... 25.9% is about 25%, so leave it at that, and 74.1% is about 75%, so leave that one there... then you have a RATIO of 1:3. 25% is one third of 75%, so your empiricle formula then comes from the ratio... 25% coresponded with N so, you have one (1) nitrogen for every three (3) Oxygen. Hense, your empirical formula is NO3.
Hope this helps!
2006-06-30 05:01:21 · answer #3 · answered by musikproz 2 · 0⤊ 1⤋
Mass (N) 25.9 and (O) 74.1
Moles (N) 1.8491150663611 and (O) 4.6314236783879
Ratio (N) 1 and (O) 2.5046703488833
Stoichiometry (N) 1 and (O) 3
From the data, a likely empirical formula is: NO3
From the data, a likely molecular formula is: N2O6
2006-06-30 05:20:53 · answer #4 · answered by knightest 2 · 0⤊ 1⤋
NO2 - Nitrogen Dioxide would be 60-30
So that could not be it
What about Nitrogen Pentoxide - N2O5. That ratio would be close. Nitrogen would be about 28% or so. I am not sure about the oxygen.
2006-06-30 05:02:50 · answer #5 · answered by Vic 3 · 1⤊ 0⤋
i hope for your sake you actually did the work and just don't have the student solution manual to check your answer. just assume you have 100 grams and it makes life easier...
N2O5
2006-06-30 04:56:43 · answer #6 · answered by shiara_blade 6 · 0⤊ 0⤋
N259O741? I"m not sure... They look like BINGO numbers to me...
Well, the other people's answers of NO3 look good to me...
2006-06-30 05:02:21 · answer #7 · answered by Anonymous · 0⤊ 0⤋
ss
2006-06-30 04:55:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋
dangit, I forget how to do this. It's been a month since Chem class! Maybe O3N1? I really dunno.
2006-06-30 04:57:25 · answer #9 · answered by c_c_runner88 3 · 0⤊ 0⤋