(x + 5)(2x2 + 4x + 2) what that answer multiplied
2006-06-29 20:43:38 · 18 answers · asked by ThAt ChIcK fLy 1 in Science & Mathematics ➔ Mathematics
multiplied by each other
2006-06-29 20:47:24 · update #1
(x+5)(2x^2+4x+2)
x(2x^2+4x+2)+5(2x^2+4x+2)
2x^3+4x^2+2x+10x^2+20x+10
2x^3+14x^2+22x+10
2006-06-29 22:37:04 · answer #1 · answered by tripleh_game_2006 2 · 0⤊ 1⤋
To multiply out (x + 5)(2x^2 + 4x + 2)...
Start by multiplying x by everything in the second set of parentheses:
2x^3 + 4x^2 + 2x
Now, do the same thing with 5 (and line the terms up this way!):
.........10x^2 + 20x + 2
Add the two lines together and you get:
2x^3 + 14x^2 + 22x + 2
This can simplify to:
2(x^3 + 7x^2 + 11x + 1)
2006-06-30 04:06:24 · answer #2 · answered by rodinia 2 · 0⤊ 0⤋
(x+5)(2x2 + 4x + 2)
I'm writing the same product that you have given like this
(x+5)(2x^2 + 4x + 2)
Okay. ^ means the right side number is the power of the leftside character.
(x+5)(2x^2 + 4x + 2)
= x (2x^2 + 4x + 2) + 5 (2x^2 + 4x + 2)
= (2x^3 + 4x^2 + 2x) + (10x^2 + 20x + 10)
= 2x^3 + 14x^2 + 22x + 10
This is the answer
2006-06-30 04:00:26 · answer #3 · answered by Sherlock Holmes 6 · 0⤊ 0⤋
Easy...
Multiply x by (2x squared + 4x + 2) then multiply 5 by (2x squared + 4x + 2) and add them. Off the top of my head I see it as 2x cubed + 4x squared + 2x, then to that we add 10x squared + 20x + 10. The total should be 2x cubed + 14x squared + 22x + 10 if I did it right. I didn't write it down; just shot it out of my massive brain on the fly. You can do these problems; they are not hard. Just take them apart, do the mathematical operations required and put them back together again. They just look hard when they are all in one piece. You can do it!
2006-06-30 03:59:35 · answer #4 · answered by christopher s 5 · 0⤊ 0⤋
PEMDAS:
Parentheses, Exponents, Multiply, Divide, Add, then Subtract.
Just do these in this order, take your time, and it will look like this:
(x+5) (4+4x+2)
4x+4x^2+2x+20+20x+10
4x^2+26x+30 =FINAL ANSWER
2006-06-30 03:51:58 · answer #5 · answered by lanneypoo4u 2 · 0⤊ 0⤋
(x + 5)(2x^2 + 4x + 2)
2(x + 5)(x^2 + 2x + 1)
2(x^3 + 2x^2 + x + 5x^2 + 10x + 5)
2(x^3 + (2 + 5)x^2 + (1 + 10)x + 5)
2(x^3 + 7x^2 + 11x + 5)
2x^3 + 14x^2 + 22x + 10
2006-06-30 06:54:38 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
(x + 5)(2x2 + 4x + 2) =
{x(2x2 + 4x + 2)} + {5(2x2 + 4x + 2)} =
{2x3 + 4x2 + 2x} + {10x2 + 20x + 10} =
2x3 + 4x2 + 2x + 10x2 + 20x + 10 =
2x3 + 14x2 + 22x + 10
2006-06-30 04:43:38 · answer #7 · answered by Thermo 6 · 0⤊ 0⤋
(x+5)(2x2 + 4x+2)
= (x+5)(4 + 4x +2)
= (x+5)(4x+6)
= [x(4x+6)]+[5(4x+6)]
= [4x^2+6x]+[20x+30]
= 4x^2+6x+20x+30
= 4x^2+26x+30 --- Ans.
2006-06-30 03:51:37 · answer #8 · answered by Robin 1 · 0⤊ 0⤋
(x+5)*(2x2+4x+2)
(x+5)*(4x+6)
4x(2)+6x+20x+30
4x.x+26x+30
because20*6=120
4x.x+20x+6x+30........by expanding
4x(x+5)+6(x+5)
therefore the answer is : (x+5) and (4x+6).
2006-06-30 03:53:34 · answer #9 · answered by Anonymous · 0⤊ 0⤋
2x^3+14x^2+22x+10
2006-06-30 03:47:22 · answer #10 · answered by bReAd-WiNnEr 3 · 0⤊ 0⤋
2(x+5)(x2+2x+1)
2(x+5)(x+1)2
2(x3+2x2+x+x2+10x+5)
2(x3+3x2+11x+5)
2x3+6x2+22x+10 ans
2006-06-30 03:47:01 · answer #11 · answered by Gunjit M 2 · 0⤊ 0⤋