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in the equation w=2/(z^3), if the value of w is multipled by 1/8, then the value of z is multipled by what number?

the answer is 2

can you please explain to me how to get that answer? thanks! =]

2006-06-29 19:24:41 · 4 answers · asked by coralflower 3 in Education & Reference Homework Help

4 answers

First, the question gives you an equation, meaning that both sides must be equal to each other. So, first do what the question tells you to do by multiplying w by (1/8). Now, because it is an equation, you must do the same thing to the other side with z. Once you multiply the right side by (1/8) you get (1/8) * (2)/(z^3). Don't simplify here because what the question is asking you to do is to put the (1/8) factor inside the z^3 factor. Since z is cubed, just think what number cubed will give me 8? The answer is 2, so the point of the question is that the equation can be written as (1/8)w=2/((2z)^3). Notice that the 2 is in the parenthesis with z, so it is also cubed, giving you a factor of 1/8.

2006-06-29 19:38:15 · answer #1 · answered by d_izzygirl 2 · 0 0

w is inversly proportional to z.
and the relation is degree 3

Therefore when W is multiplied by 1/8
then z must be mul by cuberot of the reciprocal

2006-06-30 04:27:28 · answer #2 · answered by chella 1 · 0 0

you sure they arnt the same variable, like so that the equation is 1/8z=2/(z^3)..

2006-06-30 02:51:48 · answer #3 · answered by David 5 · 0 0

w=2/z^3
1/8*w=(2/z^3)*1/8
=2/(z^3*2^3)
=2/(2z)^3
.................................
so thats why answer is 2
if you have any other problem in math then you can mail me
khizra64@yahoo.com

2006-06-30 02:36:36 · answer #4 · answered by khizra64 1 · 0 0

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