2006-06-29 18:41:36 · 13 answers · asked by The fan 2 in Science & Mathematics ➔ Mathematics
unsolvable because it is incomplete...where is the other bracket to close the brackets with the one after the 4?
2006-06-29 18:45:51 · answer #1 · answered by old dude 5 · 0⤊ 0⤋
your equation is incomplete. if your equation is 18+4[7+3(9/3)+2], then here is how you work it out:
18+4[7+3(9/3)+2]
= 18+4[7+3(3)+2]
= 18+4[7+9+2]
= 18+4[18]
= 18+72
= 90
2006-06-29 19:35:27 · answer #2 · answered by whitelighter 4 · 0⤊ 0⤋
=90 really easy isnt it?
3(9/3)=9
7+9+2=18
4(18)=72
& finally 18+72=90
of course your answer will be this if there is a braket at the end to show the limitation!
2006-06-29 18:51:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
90
2006-06-29 18:49:12 · answer #4 · answered by Anirban 2 · 0⤊ 0⤋
90
2006-06-29 18:45:34 · answer #5 · answered by blue_bee 4 · 0⤊ 0⤋
84
2006-06-29 18:54:32 · answer #6 · answered by Few Man Chew 1 · 0⤊ 0⤋
140
2006-06-29 18:50:52 · answer #7 · answered by Anonymous · 0⤊ 0⤋
704
2006-06-29 18:45:55 · answer #8 · answered by raquel13 1 · 0⤊ 0⤋
Ninety
2006-06-29 19:00:26 · answer #9 · answered by jenoosia 2 · 0⤊ 0⤋
= 40.
2006-06-29 18:44:05 · answer #10 · answered by Angus. 4 · 0⤊ 0⤋