Ive done most of my final except 2 problems i just can't get. They both deal with probability.
1)A group is composed by choosing 6 people from 5 boys and 4 girls. What is the probability that the group will have 3 girls?
2)A ball is drawn from a bag containing 13 red balls numbered 1-13, and 5 white balls numbered 14-18. What is the probability that
a) the ball is not even-numbered?
b)the ball is red and even-numbered?
c)the ball is red or even-numbered?
d)the ball is niether red nor even-numbered?
Any help would be appreciated. Thx
2006-06-29 10:09:16 · 9 answers · asked by Anonymous in Education & Reference ➔ Homework Help
The teacher gave us this final as a take home test to turn it in the day of the final. Ive done all of them except these 2.
2006-06-29 10:17:39 · update #1
1) 90% cuz most people rather have girls in the group...
2a)there's 9 odd balls out of 18 so its 50/50
b)there's 6 red evens so it's 33.333% probability almost
c)that includes 6 red and 3 white evens... 9 out of 18= 50%
d)opposite of previous is oops trick ? only 2 white oddballs... odds are 1/9= like about 11%
2006-07-12 19:29:20 · answer #1 · answered by Anonymous · 0⤊ 0⤋
P(A) = The Number Of Ways Event A Can Occur /The Total Number Of Possible Outcomes
Ex. 2).a How many are not even numbered?/ How many balls are there? That's you're answer! Check site below for more help.
2006-06-29 10:20:23 · answer #2 · answered by JAK 3 · 0⤊ 0⤋
It is about Combinations.
FIRST: You have to choose six people from from 9 (ie, four girls and five boys).
It is 5C2*4C4 + 5C3*4C3 + 5C4*4C2 + 5C5*5C1
=10*1 + 10*4 + 5*6 + 1*5
=10 + 40 + 30 + 5
=85.
The probability that the group will have 3 girls is 40/85 = 8/17
(Note: 4C3 means "choose three girls from four girls.")
(2)Could do #2 but it is getting long.
2006-06-29 10:35:50 · answer #3 · answered by J_humor 2 · 0⤊ 0⤋
if u live in pak then find out a book and key book of mr.sher muhammad chudhary for 3rd year and u can fine out ur answer in chapter of probability..i think u can find same to same problems
2006-06-29 10:21:29 · answer #4 · answered by anonymous 2 · 0⤊ 0⤋
If it were for your self-benefit, then I would help. But I am NOT going to help you cheat if it's for a higher grade (especially a final) that you didn't earn yourself. Figure it out yourself.
2006-06-29 10:16:45 · answer #5 · answered by Huey 4 · 0⤊ 0⤋
probability!!sorry,i forgot...i've learned this and i knew how to solve this.this a familiar questions.so keep that in mind you know the answer coz i just cant think to solve this....sorry...:(
2006-07-12 01:41:08 · answer #6 · answered by me__mine 2 · 0⤊ 0⤋
if this is for your final should you really be getting help with it? i dont really feel comfortable with that . . .
2006-06-29 10:13:59 · answer #7 · answered by lebeauciel 3 · 0⤊ 0⤋
Nice question....
2006-07-13 01:16:55 · answer #8 · answered by doable_rods 5 · 0⤊ 0⤋
did anyone answer u yet?
2006-06-29 10:13:01 · answer #9 · answered by ? 1 · 0⤊ 0⤋