For a human body falling though air in a spread-eagle position, the numerical value of the constant D is about D = 0.250 kg/m.
What value of D is required to make v_t = 42.0 m/s the terminal velocity of a skydiver of mass 85.0 kg? answer in kg/m
Take the free fall acceleration to be g = 9.80 m/s^2.
If the sky diver's daughter, whose mass is 40.0 kg, is falling through the air and has the same D (D=0.25 kg/m) as her father, what is the daughter's terminal speed?
Im not sure if D is drag constant, question does not clarify.
2006-06-29
09:14:06
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5 answers
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asked by
Sagely
4
in
Science & Mathematics
➔ Physics
enlighten me if you can solve this
2006-06-29
09:14:50 ·
update #1