How do I write an equation for this line?

Question

How would I go about doing the following:

Write an equation for the line that passes through the point (7,5) and is perpendicular to the line -7x-9y=14 ?

Thanks in advance, I really appreciate it!

Dog-Trainer- I'm trying to learn how to do it :P

I think the answer is y=9/7 x-4 but I am not entirely sure.....

Answer 1

The equation for a line in slope-intercept form is:

y=mx+b

where m is the slope, and b is the y-intercept.

First you need to rewrite the given equation to get the slope, because the slope of a line perpendicular is the negative reciprocal:

y= (-14/9) - (7/9)x

So the slope of the perpendicular line is the negative reciprocal of -7/9, which is +9/7

So take that slope and the given point, and plug it into the y=mx+b equztion to get your answer:

5=(9/7)(7) + b

b=5-(9/7)(7)

b=-4

Equation:

y=(9/7)x - 4

Answer 2

First you explicit y..... y = (-7/9)x - 14/9
The inclination of the perpendicular is 9/7(inverse and symmetric)
The most simple form for the equation is: y - b = m(x -a) where (a,b) are coordinates of the point and m is the inclination.
So, the result is: y - 5 = (9/7)(x - 7)
You may put the equation in other form: 9x - 7y + 14 = 0

Answer 3

whats up, Graphing this linear equation would extremely a lot help you visualize each little thing you want. do not ignore that the overall sort, y = mx + b tells you each little thing you want to confirm about an equation. therefore, you do not ignore that b = 5 because it crosses the y - axis at 5. Now, because you realize it crosses the x - axis at 3, draw a line from (0.5) to (3,0). you'll note that it really is a lowering functionality so that you'll desire a adverse verify in the front of the "x" time period. you'll see after graphing that you bypass down 5 places, and over to the right 3, that's your slope. consequently your equation is ... y = -(5/3)x + 5 wish this allows.

Answer 4

slope of the given line is -7/9
hence the slope of the line perpendicular will be 9/7
its equation is y=9/7x+c
this passes thr (7,5)
subsitute for x n y these values n get c

Answer 5

first you need to put your equation in Slope-intercept form..

y = mx +b

where m is the slope of the line and b is the y intercept value

perpendicular lines have negative inverse slopes.. so you just write the new equation with y= -(1/m)x + k (use k because you do not know the y-intercept at this time..

plug in the values for your new point.. 5= -(1/m)7+k and solve for k

then write out your answer equation.

Answer 6

-7x-9y=14 ==> y=(7x+14)/-9 ==> y=(-7x/9)-9/14

therefore the slope you need is 9/7

therefore y=(9x/7)+b, sub in (7,5)
==> 5=9(7)+b
==> b=-58

therefore the equation is y=(9x/7)-58

Answer 7

-7x - 9y = 14
-9y = 7x + 14
y = (-7/9)x - (14/9)

m = (-7/9)

perpendicular slope is (9/7)

(7,5), m = (9/7)
5 = (9/7)(7) + b
5 = 9 + b
b = -4

ANS : y = (9/7)x - 4

so you were correct

Answer 8

The slope in negative reciprocal of the slope of that equation.
and you plug in those numbers to the equation y=mx + b
with m being your new slope!

Answer 9

I would really love to help you. I just bombed my linear algebra final, so I would guess that I'm not qualified. Good luck!

Answer 10

Go to webmath.com to find the answer. It helped me.