English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Two hours after a truck leaves Phoenix traveling at 45 miles per hour, a car leaves to overtake the truck. If it takes the car ten hours to catch the truck, what was the car's speed?

2006-06-29 06:59:12 · 7 answers · asked by Rocstarr 2 in Science & Mathematics Mathematics

7 answers

54 mph.

Truck: 2 hours + 10 hours at 45 miles an hour = 12 hours at 45 mph = 540 miles.

Car: 540 miles in 10 hours = 54 miles an hour.

This is assuming no stops were made and the bladders involved were made of steel.

2006-06-29 07:02:49 · answer #1 · answered by cirestan 6 · 0 0

Distance covered by the car when overtaken: 45mph * (2 hours headstart + 10 hours for car to catch up) =
45*12 = 540 miles

Car's speed: = 540 miles / 10 hours = 54 mph.

2006-06-29 14:04:50 · answer #2 · answered by DR 5 · 0 0

truck travels for 12 hours (2+10)
distance travelled = 12*45 = 540

Car travels same distance in 10hours

speed of car = 540/10 = 54 miles

2006-06-29 14:04:57 · answer #3 · answered by mmm... 1 · 0 0

rate = distance/time
rate of truck = 45 miles/hours

the truck goes 2 hours before the car leaves
2hrs x 45mi/hr = 90mi

when the car leaves the truck is 90mi away, but still traveling 45mi/hr
after 10 hours, the truck travels 450mi
so the car catches the truck when it is 540miles away from phoenix
the car traveled 540mi in 10 hours, so that is
540/10 = 54mph

2006-06-29 14:11:18 · answer #4 · answered by Brad 4 · 0 0

Let car's speed = v

So, 10v = 90 + 45*10

or 10v = 540 or v =54 mph

2006-06-29 14:10:48 · answer #5 · answered by ag_iitkgp 7 · 0 0

53 mph

2006-06-29 14:05:48 · answer #6 · answered by whiteeagle_1975_2006 1 · 0 0

54MPH

2006-06-29 14:05:59 · answer #7 · answered by bigjerry61 4 · 0 0

fedest.com, questions and answers