The Drama Club sold 320 adult tickets and 153 student tickets for their last performance. Adult tickets were 75 cents more than student tickets. If the total receipts were $949.50, what was the price of each ticket?
2006-06-29 06:56:26 · 6 answers · asked by Rocstarr 2 in Science & Mathematics ➔ Mathematics
x= price of adult ticket
y=price of student ticket
320x + 153y = 949.50
x = y+.75
320(y+.75) + 153y = 949.50
320y + 240 + 153y = 949.50
473y + 240 = 949.50
473y = 709.50
y = 1.5
x = 2.25
I haven't done algebra in 7 years, but I got beat by Ralphy Wiggum...how embarrasing!
2006-06-29 07:05:26 · answer #1 · answered by MDPeterson42 3 · 0⤊ 0⤋
320 X + (320 * 0.75) + 153 X = 949.50
320 X + (240.00) + 153 X = 949.50
320 X + 153 X = 709.50
473 X = 709.50
X = $1.50 student tickes
X + .75 = $2.25 adult ticket
2006-06-29 14:07:36 · answer #2 · answered by wires 7 · 0⤊ 0⤋
I can help you out with this one
total money = 949.50
student tickets = s
adult tickets = a
adult tickets = student tickets + .75
a = s +.75
s = a - .75
320a + 153s = 949.5
320a + 153(a - .75) = 949.5
320a +153a - 114.75 = 949.5
473a = 1064.25
a = $2.25
s = $1.5
2006-06-29 14:05:35 · answer #3 · answered by Brad 4 · 0⤊ 0⤋
S = price of student ticket
A = price of adult ticket
A = S + .75
320*A + 153*S = 949.50
320*(S + .75) + 153*S = 949.50
320*S + 240 + 153*S = 949.50
473*S = 709.50
S = 1.50
A = S + .75 = 2.25
2006-06-29 14:06:42 · answer #4 · answered by kimmyisahotbabe 5 · 0⤊ 0⤋
320a + 153s = 949.50
a = s+.75
320(s+.75)+ 153s = 949.50
473s + 240 = 949.50
473s = 709.50
s = 1.50
a = 2.25
2006-06-29 14:02:43 · answer #5 · answered by Ralphy Wiggum 2 · 0⤊ 0⤋
320x + 153y = 949.50
y = x + .75
320(y + .75) + 153y = 949.50
320x + 240 + 153x = 949.50
473x + 240 = 949.50
473x = 709.5
x = 1.5
y = x + .75
y = 1.5 + .75
y = 2.25
Adult : $2.25
Student : $1.50
2006-06-29 16:47:20 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋