I think you mean 4x/((x+6)(x+6)) + 3/(x-6). You need a common denominator. In this case it will be (x+6)(x+6)(x-6).
So we get 4x(x-6) + 3(x+6)(x+6) as the new numerator.
This equals 4x^2-24x + 3x^2+36x+108 = 7x^2+12x+108.
Final answer: (7x^2+12x+108) / ((x+6)(x+6)(x-6))
2006-06-29 07:26:51
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answer #1
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answered by Jeff U 4
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Cross multiply
4x/(x+6)(x+6) + 3/x-6
4x (x-6) = 3 (x+6) (x+6)
4x² - 24 = 3x + 18 +3x + 18 (distributive property)
4x² = 6x + 60
4x² - 6x - 60 = 0
(2x - _ ) (2x + _ )
Find the missing numbers and solve for x, one answer might be negative, and one positive
2006-06-29 11:44:38
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answer #2
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answered by Rocio 2
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Find the Least Common Denominator...
(x-6)(x+6)(x+6)
[(4x^2 - 24x) / (x-6)(x+6)(x+6)] + [3(x+6)^2 / (x-6)(x+6)(x+6)]
Add the numerators with the least common denominator remaining as the denominator.
[4x^2 - 24x + 3(x+6)^2] / [(x-6)(x+6)(x+6)]
Factor out the numerator.
1. 4x^2 - 24x = 4x(x-6)
2. 3(x+6)^2 = 3(x+6)(x+6)
Rewrite equation.
[4x(x-6) + 3(x+6)(x+6)] / [(x-6)(x+6)(x+6)]
All the parenthetical factors cancel out, and you are left with...
4x + 3
2006-06-29 09:18:30
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answer #3
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answered by trancevanbuuren 3
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((4x)/((x + 6)(x + 6)) + (3/(x - 6))
Multiply everything by (x + 6)(x + 6)(x - 6)
(4x(x - 6) + 3((x + 6)(x + 6)))/((x + 6)(x + 6)(x - 6))
(4x^2 - 24x + 3(x^2 + 12x + 36))/((x + 6)(x + 6)(x - 6))
(4x^2 + 24x + 3x^2 + 36x + 108)/((x + 6)(x + 6)(x - 6))
(7x^2 + 60 + 108)/((x + 6)(x + 6)(x - 6))
((x + 6)(7x + 18))/((x + 6)(x + 6)(x - 6))
the (x + 6)s cancel out
(7x + 18)/((x + 6)(x - 6))
ANS : (7x + 18)/(x^2 - 36)
2006-06-29 09:53:24
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answer #4
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answered by Sherman81 6
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4x / ( (x+6) (x+6) ) + 3 / (x-6) =
( 4x (x-6) + 3 (x+6) (x+6) ) / (x+6)(x+6)(x-6) =
( 4x^2 - 24x + 3 (x^2 + 12x + 36) ) / (x+6)(x+6)(x-6) =
( 4x^2 - 24x + 3x^2 + 36x + 108) ) / (x+6)(x+6)(x-6) =
( 7x^2 + 12x + 108 ) / (x+6)(x+6)(x-6)
2006-06-29 07:26:52
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answer #5
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answered by Anonymous
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Assuming it is 3/(x-6)
4x/(x+6)^2 + 3/(x-6) = (4x(x-6)+3(x+6)^2)/(x+6)^2(x-6)
Now expand.
2006-06-29 06:59:01
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answer #6
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answered by ag_iitkgp 7
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4x/(x+6)^2 +3/(x-6)= (7x^2 + 12 x +108)/((x-6)(x+6)^2)
2006-06-29 07:57:10
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answer #7
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answered by Anonymous
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