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I am on verizon wireless and want to be on cingular. I can't get out of this stupid contract till dec of .07 is there any way you know of to get out without paying the stupid fees? I have contracts!

2006-06-28 19:10:42 · 6 answers · asked by luckycharm570 2 in Consumer Electronics Cell Phones & Plans

6 answers

Provide an address that you are "moving to" in a place where Verizon cannot provide service. if they cannot provide you service, then how can you continue with them. I had to do that with alltel. But for me, I actually had that problem. I moved from Ohio to Las Vegas and we do not have Alltel in Las Vegas so they had to let me out of the contract b/c they can't provide service where it does not exist. Look for places in Iowa or Montana. There are pockets there that Verizon does not provide service. Good luck... I've been in your shoes!!!

2006-06-28 19:15:49 · answer #1 · answered by chrissielou222 2 · 6 0

I sell cellphones for a living and to the best of my knowledge there is no way to get out of your service contract.
but if you do decide to switch i would have to say that Cingular is a very good choice, also consider sprint depending on your circumstances.

2006-06-29 02:17:31 · answer #2 · answered by tygerphlyer 2 · 0 0

No you can't. you either pay the early termination penalty or keep with them until the expiration of the contract.

2006-06-29 02:14:02 · answer #3 · answered by lelekid4ever 5 · 0 0

This is a toughy. Cell phone contracts are so tough to get out of. I'm trying to get out of one myself that my sister and I are part of as a family plan. All she could find was someone said, "Fake your death." Really, they are that tough to get out of. It's sad.

2006-06-29 02:14:00 · answer #4 · answered by pizzagirl 3 · 0 0

probably not :(

verizon is evil. honestly, they have the best coverage, but the worst customer support. they're like evil robots.

2006-06-29 02:14:35 · answer #5 · answered by Royb 2 · 0 0

nope....just like you can't get out of helping me get 2 pts

2006-06-29 02:14:22 · answer #6 · answered by Anonymous · 0 0

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