World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15.0 m/s^2.
How much horizontal force must a sprinter of mass 61.0 kg exert on the starting blocks during a start to produce this acceleration?
Which body exerts the force that propels the sprinter, the blocks or the sprinter herself?
2006-06-28 18:38:25 · 3 answers · asked by GUVNA? 1 in Science & Mathematics ➔ Physics
F = m*a
F = 61 * 15 newton (kg*m/s^2)
The force is exerted by the sprinter, but the block pushes back with equal force.
2006-06-28 19:11:11 · answer #1 · answered by gp4rts 7 · 0⤊ 9⤋
This is wrong the blocks exert the force
2014-09-16 15:01:31 · answer #2 · answered by Nia 1 · 9⤊ 0⤋
you need to calculate the fee at which it would fall freely that's something like the load x gravitational rigidity.and you need to comprehend the top it advance into dropped from, and then calculate the thrust action mandatory to equivalent that velocity by potential of pondering the load and pass of kinetic power ....or something like that
2016-10-31 21:47:51 · answer #3 · answered by ? 4 · 0⤊ 1⤋