what is a way to get 25 with two pairs of the same multiple such as 4*4 and another is 3*3 and must eqaul 25?

Question

3*3 and 4*4 but both pairs of multiples must equal 25. So 4*4=8 and 3*3=6. 3*3should equal 25 and so should 4*4

Answer 1

5x5 and
-5x-5

Answer 2

4 x 4 = 16 and 3 x 3 = 9. Then 16 + 9 = 25. That's what you meant. There are no other integers which you can square and add together to equal 25. The proof lies in the proof of the Pythagorean Theorem. What we have here is the 3-4-5 triangle. Otherwise written as 3^2 + 4^2 = 5^2. This is a unique integral solution for Pythagorean triples. They all are. But if you want negative integer solutions for 25, there is another solution. If you want to allow fractions, there is yet two more another solutions. Someone here told me to add (5, 0) but that's a degenerate solution and one mathematicians don't like to consider, because they don't lead anywhere, or produce interesting results.

Answer 3

If you're looking for Pythagorean triples, 3² + 4² = 5² is the only way to get 25 using positive integers. But (-3)² also is 9, and (-4)² is 16, so if you're not limited to positive integers, there are negative solutions.

Are you limited to integers? If not, √(17)² + √(8)² = 25.

Answer 4

This is confusing and I am not quite sure what you are looking for but 5 X 5 = 25.
3X3 = 9 and 4X4 = 16 and added together 9 + 16 = 25.

Answer 5

3*3+4*4=25, 3,4,5 are pitagoric numbers

Answer 6

5*5/(1*1)

Answer 7

5x5 and 0x0