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The function has zeroes at -6 and 0. It decreases to negative infinity as x decreases from -6. It increases to infinity as x increases from zero. The only relative maximum is at -4.

2006-06-28 15:48:48 · answer #1 · answered by Big Jim 3 · 0 0

Take the derivative of the funtion and set it equal to zero to find the minimum and maximum points:

Derivative of F(x)
F'(x) = 12x + 3x^2

0 = 12x + 3x^2
x = 0 , -4

If you were to look at the graph of this equation you would see that x = -4 is a relative maximum and x = 0 is a relative minimum

2006-06-28 21:24:05 · answer #2 · answered by Drew 2 · 0 0

42

2006-06-28 21:21:43 · answer #3 · answered by Anonymous · 0 0

The answer is 0

2006-06-28 22:11:42 · answer #4 · answered by AnGeL 4 · 0 0

WHAT following points?

2006-06-28 21:27:36 · answer #5 · answered by Steve 7 · 0 0

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