The typical adult human has a mass of about 70.0 kg.
What force does a full moon exert on such a human when it is directly overhead with its center a distance 3.86×10^5 km away?
Take the gravitational constant to be G = 6.67×10^−11 N*m^2/kg^2, and the mass of the Moon to be 7.35×10^22 kg.
thanks
2006-06-28 13:31:59 · 10 answers · asked by Conscious 1 in Science & Mathematics ➔ Physics
230*10^-5N a very small amount. formula is Gm1m2/d^2. convert distance in mts.
6.67*10^-11 * 70 * 7.35*10^22 / (3.86 * 10^8)^2
6.67*70*7.35 * 10^-5 /3.86 * 3.86
230.322 * 10^-5
2006-06-28 13:49:26 · answer #1 · answered by bhaskar 1 · 1⤊ 0⤋
I would actually equate this, but its been a while since physics and I don't remember how!
unfortunately there's another few factors that would affect this, for instance whether the moon is full or not.
But I could speculate based on what I know about tides. A spring tide occurs when the moon is full (and at some point the moon would be directly above) and depending on the location of the water on the planet, it'll rise several feet higher. But, people are small, and oceans are very large.
My conclusion is that it wouldn't affect a person that much, or that noticeably.
sorry I can't do better, but I don't remember how to equate this!
2006-06-28 20:47:46 · answer #2 · answered by solitusfactum 3 · 0⤊ 0⤋
Since F = (G*m1*m2)/(d^2)
and given G, m1 (mass of adult human), m2 (mass of moon), and d (distance to moon), F can be solved for easily. In this case, F is the force of attraction between the human and the moon, NOT the resultant weight (force of earth's attraction) of the human.
2006-06-28 20:39:18 · answer #3 · answered by JPH 1 · 0⤊ 0⤋
I think the force is equal to (G*m1*m2)/(r^2) where r is the distance between the two objects, m1 is the mass of object 1, m2 is the mass of object 2, and G is the gravitational constant
2006-06-28 20:36:21 · answer #4 · answered by harshil.patel@sbcglobal.net 2 · 0⤊ 0⤋
Magic
2006-06-30 19:09:56 · answer #5 · answered by 22 2 · 0⤊ 0⤋
solitusfactum - the question specified a full moon. That is not relavant anyway because the entire moon is there even if you can't see it.
2006-06-28 22:09:34 · answer #6 · answered by STEVEN F 7 · 0⤊ 0⤋
Sounds like homework.
2006-06-28 20:40:28 · answer #7 · answered by linuxfortravelers 3 · 0⤊ 0⤋
A big amount!
2006-06-28 20:34:43 · answer #8 · answered by My Avatar 4 · 0⤊ 0⤋
I hope no one answers this. do you own homework.
2006-06-28 20:34:32 · answer #9 · answered by rogdogg187 5 · 0⤊ 0⤋
what??
2006-06-28 20:35:41 · answer #10 · answered by alexis21895 2 · 0⤊ 0⤋