If it is 0 degrees farenheight today and it's supposed to be twice as cold tommorow how cold will it be?

Answer 1

C=(5/9)(F - 32)

C = (5/9)(0 - 32)
C = (5/9)(-32)
C = -160/9
C = -17 7/9

Double that, and you get

C = -35 5/9

F = (9/5)C + 32

F = (9/5)(-35 5/9) + 32
F = (-320/5) + 32
F = -64 + 32
F = -32

ANS : -32°F

Answer 2

"Twice as cold" has to be relative to some objective standard. And when we measure temperature, we are measuring the amount of heat--cold is just the absence of heat. This is one of those things that people often say, but it really doesn't make much sense (which is the reason you offered it as a question, right?).

So let's say there are two ways of answering. One might be to say that the "objective" point is freezing, which happens at 32 degrees Farenheit. So today there are 32 fewer degrees of heat; if it is "twice as cold tomorrow," that would seem to put tomorrow's temperature at -32 degrees Farenheit.

However, since temperature measures heat, a better "objective" comparison would be made to absolute zero (0 degrees Kelvin), which happens at -460 degrees Farenheit (rounding off). That means that today's temperature contains 460 degrees of heat; if there is only half as much tomorrow ("twice as cold" = "half as hot"), then tomorrow's temperature will be -230 degrees Farenheit.

In truth, I'm not sure that either of these is really what a person means when they say "twice as cold"--but I'm not sure what they really do mean.

Answer 3

Temperature is a measure of the energy (used very general here) in a system. If one assumes that 0 degrees fahrenheit is equivalent to energy X, then twice as cold would PROBABLY mean the fahrenheit equivalent of X/2.

Absolute zero, -459 degrees Fahrenheit, represents 0 energy. Thus X is proportional to 0-(-459), or 459, degrees Fahrenheit. This means that X/2 is proportional to 459/2 or 229.5 degrees, which, when subtracted from the starting temperature, 0, means twice as cold = -229.5 degrees Fahrenheit.

Which is without windchill, by the way.

Answer 4

It is not possible to be twice as cold or hot - only the measurement can be twice as much.
0 F equals minus 17 Celsius.
0 F x 2 now equals 0 F
-but- (-17) C x 2 would equal (-34) C which is minus 29 F.

Long story short: it is an expression that does not translate into reality.

Answer 5

0 degrees farenheight. 0 times 2 equals 0.

Answer 6

It can't be "twice as cold". Cold is a description like "blue". Something can't be "twice as blue" either. The weather can be cold-er than today by the temperature being even lower. But, "twice as cold" isn't a valid description.
Or, you can do it this way if you really want an answer. 0 Fahrenheit equals -17.778 Celcius. So, if you double that temperature you get -35.556. Convert back to Fahrenheit and you get -32.008. Twice as cold.

Answer 7

The reason it doesn't make sense to talk about one day being "twice as cold" as another is that on the fahrenheit temperature scale, the zero point is arbitrary. It is also arbitrary on the centigrade scale. The only temperature scale on which the zero is not arbitrary is the Kelvin scale. On the Kelvin scale, absolute zero represents the temperature at which all motion, even atomic motion, ceases. It is impossible to get any colder than that, so if it were zero degrees Kelvin today, it couldn't be twice as cold tomorrow. (And we'd all be dead.)

Answer 8

There is no such thing as 'cold' scientifically, it is undefined. The bottom of the scale is -459 deg f. If it is twice as warm as -229.5 deg f, it will be zero. The Fahrenheit scale is not the real number line, hence mathematical operation on zero are semantics.

Added:
To my compatriots who have converted to Celsius to do the math, why did you not convert to Kelvin? You did not remove half the temperature when you multiplied your negative C by two.

Answer 9

-32 degrees Farenheight.

Answer 10

First of all, you cannot dell with 0 F for this case, that mean you must first convert it to C;
OK
0 F = -32 C
double the temp. which is in C you will get,
2 * (-32) = -64 C
NOW, convert the result to F
((-64) + 32) * 5 / 9 = -17.778 F
And that the answer, ... With regards.

Answer 11

You need to convert to an absolute temperature scale such as Kelvin, do the math, and then convert back to Fahrenheit. 0 degrees F is -17.78 Celsius [(0-32)*9/5), which is 255.37 Kelvin
(-17.78 + 273.15). Half of 255.37K is 127.685K, which is half as hot (twice as cold) as 255.37K (which is 0 Fahrenheit). Convert 127.685K to Fahrenheit, and you have the answer. I get
-229.6.