Two runners start simultaneously from the same point on a circular track of length 198 m and run in the same direction. One runs at a constant speed of 5.30 m/s and the other at a constant speed of 6.45 m/s.
When will the fast one lap the slower one?
How far from the starting point will the slower one have run?
2006-06-28 08:46:09 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
How far from the starting point will the faster one have to run?
2006-06-28 09:13:41 · update #1
The difference in speed is 6.45-5.30 = 1.15 m/s.
The track is 198 m long - so the faster runner must catch up by this much to lap the slower.
This will take 198/1.15 seconds.
The slower one will have run 198 x 5.30/1.15 m.
2006-06-28 08:51:47 · answer #1 · answered by Epidavros 4 · 0⤊ 0⤋
x1=0+5.30t
x2=0+6.45t
find t when x2=x1+198
6.45t=5.30t+198
(6.45-5.30)t = 198
t= (198/1.15) sec
This is the proper way to solve.
2006-06-28 09:23:34 · answer #2 · answered by bequalming 5 · 0⤊ 0⤋
Well the first step is to figure out how much faster the quick man is running than the slow man.
6.45m/s - 5.30m/s = 1.15m/s
Then you divide 198m by 1.15m/s to determine how long it takes to complete an entire lap at that speed differential.
198m / 1.15m/s = 172.17s
Answer: It would take 172.17 seconds, or 2 minutes 52.17 seconds.
2006-06-28 08:53:56 · answer #3 · answered by P.I. Joe 6 · 0⤊ 0⤋