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I skipped class on the day we covered this & now I'm paying for it! My instructions in my book says: Use substitution to find each indefinite integral. Problem #1 has the swirly line (integral symbol?) then says (3x(squared) - 5) all to the 4th 2x dx. I am so lost. Please tell me how to solve this!!!

2006-06-28 07:47:37 · 5 answers · asked by Brooke~* 3 in Education & Reference Homework Help

5 answers

you can go to this site, you enter in the problem and it solves it for you....http://integrals.wolfram.com/index.jsp

2006-06-28 08:02:31 · answer #1 · answered by Pink Panther 1 · 0 0

Wow, just show how hopeless and backwards the American education system is. In university and still don't understand damned integration? In Asian countries, they learn intergration at 16 yrs old, so let me solve this intergration prolem for you. To the first problem, the answer is ((3x)^1.5)/1.5 - 5x + c. But I don't understand the second part of your question, the " all to the 4th 2x dx." What the hell do you mean by all to the fourth?

2006-06-30 01:30:33 · answer #2 · answered by Dallas M 2 · 0 1

the elementary theorem of critical calculus is int 3-a million(f(x))=F(3)-F(a million) F(x) skill after its integrated then u do the subtraction this may discover you the realm less than the curve from x=a million to x=3 there also are indefinate integrals which skill its asking you in looking the realm less than the finished graph from -countless to countless it would want to also be used to discover the size of the remedy or maybe ind 3-D. with an same features. in the graphs something less than x-axis is seen adverse and above it really is seen efficient so once you 'v both in a critical u subtract the negatives the single less than the x-axis and upload the positives. integration is likewise favourite as anti-by-product

2016-11-15 09:17:29 · answer #3 · answered by ? 4 · 0 0

I would strongly suggest that you go to your calculus instructor after you have read the book and obtained some notes from another student. This question cannot be answered in a short paragraph.

2006-06-28 12:02:40 · answer #4 · answered by LARRY R 4 · 1 0

I could, but where would be the fun in that?

2006-06-28 07:50:44 · answer #5 · answered by Zippy 7 · 1 0

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