How do u calculate the volume or molar concentration of an acid or base required to neutralize the other.?

Question

HELP ME PLEASE! TEST TODAY AT 6

Answer 1

I think this is how you do it:
acid and base is measured in terms of pH and pOH. as you know, the H makes it acidic and the OH makes it basic, and if you mix an H and OH, you get water, which is to say it was neutralized.
So, let's say you have HBr with a pH of 4. You that pH is a measure of the concentration of H present in the mixture. So, to get the actual number you do -10ph, and you'll get a number like 10^-5 or something. So, to neutralize that many Hs, that's how many OH's you need. so, you'll need a pOH 4, which is the same thing is a pH of 10 (pOH = 14 - pH).
hope that helps, good luck. and read the book, and do some of hte exercised in the book.

Answer 2

First calculate the number of moles of acid or base to be neutralized. If it is a strong acid then you will need a strong base to neutralize it. If both the acid and the base are strong then the number of moles of acid/base to be neutralized will equal the number of moles of the other used to neutralize. You should know the molar concentration of the other. Dividing the known molar concentration by the number of moles of this acid/base required will give you its volume.
The second thing you can do is
Concentration of acid * Acid Volume = Concentration of base * Volume of base
This only works with strong acids and bases.

Answer 3

Concentration of Acid x Volume of Acid = Concentration of Base x Volume of Base

Answer 4

you have the volume and concentration of one and calculate the # of moles. if the acid/base ration is 1:1 that's how much other other it will take to neutralize. then you figure out either the volume or concentration using the molarity equation M=mol/L

Answer 5

Just use the equation

Cacid*Vacid=Cbase*Vbase

where C is concentration in mole/lt (M)
and V the volume in ml or lt, whichever suits you as long as both Vacid and Vbase have the same unit.