3x = 2y + 6
x = (2y + 6) / 3
2006-06-28 02:34:31
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answer #1
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answered by jimbob 6
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3x - 2y = 6
2x + y = 11
Solve for y in the second equation: y = 11 - 2x
Substitute this value of y into the first equation:
3x - 2(11 - 2x) = 6
Solve for x: 3x - 22 + 4x = 6
7x = 28
x = 4
Use the equation that gives y to solve for y by substituting in the x-value: y = 11 - 2(4)
= 11 - 8
= 3
Solution: (4,3)
2006-06-28 02:34:32
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answer #2
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answered by Anonymous
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3x-2y=6
+2y +2y
3x=6 +2y
/3 /3
x=2+2/3y
2006-06-28 02:53:51
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answer #3
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answered by lovely 4
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x = 2 + 2/3 y
2006-06-28 02:31:29
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answer #4
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answered by David S 2
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x=6+2y/3
2006-06-28 02:42:53
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answer #5
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answered by Anonymous
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3x-2y=6
x=(6+2y)/3
if the x value is only in the whole nos, then ...
if y=3, then x=4
if y=6,then x=6
y should be a multiple of 3 to get the x in the whole nos.
2006-06-28 03:08:41
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answer #6
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answered by Manis 4
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3x - 2y = 6
3x = 2y + 6
x = (2/3)y + 2
2006-06-28 05:15:11
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answer #7
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answered by Sherman81 6
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3x-2y=6
3x=6+2y
x=6+2y/3
hence x=6+2y/3
2006-06-28 02:35:01
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answer #8
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answered by Anonymous
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y=3
x=4
3(X) - 2(Y) = 3(4) -2(3) = 6
12 - 6 = 6
i swear i've answered this in college before, must be right..is it?
2006-06-28 02:37:04
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answer #9
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answered by jen_mauve 1
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3x-2y=6
Add 2y to both sides, which will eliminate -2y and isolate 3x.
3x=2y-6
divide both sides by 3
x=2y/3-2
If I remember correctly.
2006-06-28 02:32:36
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answer #10
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answered by Shan 1
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