a shop keeper sold 4 teles and 2 vcr's for $4080 total. price of vcr is 2/5 of tele.how much is each vcr?

0 ⤊

a shop keeper sold 4 teles and 2 vcr's for $4080 total. price of vcr is 2/5 of tele.how much is each vcr?

2006-06-27 21:24:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

Let T = price for tele, V = price for vcr
So, V = (2/5)T

4T + 2V = 4080
4T + 2(2/5)T = 4080
4T + (4/5)T = 4080
(4 + 4/5)T = 4080
(24/5)T = 4080
T = 4080*5/24 = 850

V = (2/5)T = (2/5)*850 = 340

2006-06-27 22:05:09 · answer #1 · answered by Pinsir003 3 · 0⤊ 0⤋

$340

2006-06-27 21:51:33 · answer #2 · answered by joabhi 2 · 0⤊ 0⤋

$340

2006-06-27 21:33:02 · answer #3 · answered by Rain 2 · 0⤊ 0⤋

4x + 2y = 4080
v = (2/5)x

4x + 2((2/5)x) = 4080
4x + (4/5)x = 4080
20x + 4x = 20400
24x = 20400
x = 850

v = (2/5)(850)
v = (1700/5)
v = 340

TV = $850
VCR = $340

ANS : $340

2006-06-28 05:37:35 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋