2006-06-27 16:51:13 · 12 answers · asked by jonny_sierra 1 in Science & Mathematics ➔ Mathematics
And your question is?
2006-06-27 16:54:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
sorry couldn't get ur question
anyways if ur looking for lowest values of f(x) its
derive both side wrt to x
f'(x)=4x
now put f'(x)=0
so, 4x=0
=>x=0
so f(x) has minima i.e. minimum value at x=0
i.e.
2*0-98=-98
-98 is the answer
2006-06-28 00:04:33 · answer #2 · answered by The man who knows 2 · 0⤊ 0⤋
And ...? Are you trying to solve for x?
2x^2 - 98 = 0
2x^2 = 98
x^2 = 49
x = +/- 7
2006-06-27 23:54:50 · answer #3 · answered by tdw 4 · 0⤊ 0⤋
f(x)=2x^2-98
f(x)=2(x^2-49)
f(x)=2(x+7)(x-7)
what is your question by the way???
roots are -7 and +7
2006-06-28 00:11:13 · answer #4 · answered by Croasis 3 · 0⤊ 0⤋
Es una función exponencial donde es necesario graficar remplazando valores de x con respecto a y.
2006-06-28 13:27:47 · answer #5 · answered by RICHY 1 · 0⤊ 0⤋
f(x) = 2x^2 - 98
f(x) = 2(x^2 - 49)
f(x) = 2(x - 7)(x + 7)
2006-06-28 00:08:27 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
x =?????? or is this the value of f(x)? and you just want to substitute the expression for in place of x in an equation that isnt there???
2006-06-27 23:57:05 · answer #7 · answered by nick_15986 1 · 0⤊ 0⤋
f(x)=2(x"squared"-48)
2006-06-28 01:50:16 · answer #8 · answered by clarinetgenius12 2 · 0⤊ 0⤋
yep
2006-06-27 23:55:22 · answer #9 · answered by Anonymous · 0⤊ 0⤋
omg i am so sorry. i totally forgot how to do this!!! SORRY! >.<
2006-06-27 23:54:50 · answer #10 · answered by gtfoammas! 3 · 0⤊ 0⤋