***********************
Im not sure
but if you want
a second opinion....
..YOUR UGLY!!!
**************************
2006-07-06 04:50:10
·
answer #1
·
answered by El Mariachi 4
·
1⤊
1⤋
Why would the doctor doctor any other way apart from the way they usually doctor? Whether a doctor doctors a doctor or a doctor doctors a doctor's doctor, that doctor will still doctor the way that doctor doctors.
2006-06-27 15:34:29
·
answer #2
·
answered by Bapboy 4
·
0⤊
0⤋
I think the doctor who doctors the doctor would definitely doctor another doctor who would doctor a doctor in the way the doctor doctors.
2006-06-27 14:58:27
·
answer #3
·
answered by itty 7
·
0⤊
0⤋
He doctors the way the doctor who doctor doctors.
2006-07-10 11:57:30
·
answer #4
·
answered by fantasy_gamer_uk 2
·
0⤊
0⤋
Depends if the doctor likes the way that the doctor who doctors the doctor. But what if neither of the doctors like each other?
2006-07-09 13:30:46
·
answer #5
·
answered by dabugster20 2
·
0⤊
0⤋
I believe the doctor who doctors the doctor will not doctor the doctor the same way the doctor would expect the doctor to doctor him.
2006-07-06 09:36:47
·
answer #6
·
answered by Samba Queen 5
·
0⤊
0⤋
The doctor doctors the way the doctor who doctors doctors of course. Why would the doctor doctor the doctor the way the doctor he is doctoring doctors if the doctor is used to doctoring the way he himself doctors?
2006-06-28 01:08:38
·
answer #7
·
answered by undir 7
·
0⤊
0⤋
No, the doctor doctors the way the doctor who doctors doctors doctors. Or whatever. Lol
2006-06-27 20:33:10
·
answer #8
·
answered by * 5
·
0⤊
0⤋
The first doctor treats the second doctor the way the first doctor treats anyone. If the first doctor tried to treat like the second doctor, he wouldn't be the doctor the doctor needs.
2006-06-27 14:56:58
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
But who would be the doctor
2006-06-27 14:55:21
·
answer #10
·
answered by Judas Rabbi 7
·
0⤊
0⤋
Well the answer needs some doctoring
2006-07-08 23:16:27
·
answer #11
·
answered by muscle_horse 2
·
0⤊
0⤋