2006-06-27 13:33:45 · 7 answers · asked by thecueballkid 1 in Science & Mathematics ➔ Mathematics
t = ln(13) / 0.65
2006-06-27 13:38:15 · answer #1 · answered by dcg 1 · 0⤊ 0⤋
Solve,
e^(0.65t) = 13
Natural log both sides,
ln( e^(0.65t)) = ln (13)
(0.65t) ln (e) = ln (13)
(0.65t) (1) = ln (13)
t = ln (13) / 0.65
t = 3.94607593455621
2006-06-27 21:33:33 · answer #2 · answered by ideaquest 7 · 0⤊ 0⤋
ln(e^(0.65t)) = ln(13)
0.65t = ln(13)
t = ln(13) / 0.65
t = 3.9461
2006-06-27 20:52:44 · answer #3 · answered by meow 3 · 0⤊ 0⤋
t = square root e+13/0.65
2006-06-27 20:43:56 · answer #4 · answered by urbanman_15 1 · 0⤊ 0⤋
e^(.65t) = 13
.65t = ln(13)
t = (ln(13))/.65
t = (ln(13))/(65/100)
t = (ln(13)/1)/(13/20)
t = (ln(13)/1)*(20/13)
t = (20ln(13))/13
2006-06-27 20:50:26 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
t=ln13/0.65 = 3.946075935.....
2006-06-27 20:54:35 · answer #6 · answered by Don Pepe 1 · 0⤊ 0⤋
It is approximately
3.946075934556210363159211448562028622777335299631087871413916170251484103576015660614730251446906905798858757065788802510049468449210133867423489410727
And you are funny:)
2006-06-27 20:42:16 · answer #7 · answered by dj_homa 1 · 0⤊ 0⤋