Solve the inequality in terms of intevals: 4x< 2x + 1 ≤ 3x + 2
2006-06-27 11:21:50 · 8 answers · asked by stillborndesires01 1 in Science & Mathematics ➔ Mathematics
Show work, please.
2006-06-27 11:22:10 · update #1
2x<1 , x<0.5
-1
-1< x<0.5
2006-06-27 11:30:26 · answer #1 · answered by prune 3 · 0⤊ 0⤋
-1≤ x < 1/2
2006-06-27 13:47:03 · answer #2 · answered by Don Pepe 1 · 0⤊ 0⤋
4x < 2x + 1 <= 3x + 2
4x < 2x + 1
2x < 1
x < (1/2)
2x + 1 <= 3x + 2
-x <= 1
x >= -1
-1 <= x < (1/2)
2006-06-27 13:45:03 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
subtract 2x from all parts of this inequality to get
2006-06-27 11:33:09
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answer #4
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answered by Aslan 6
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2x < 1 =< x +2
Then we can break it down into further parts
2x<1
implies that x<1/2
second part
1=
so combining both parts we find that x lies in the band
-1=
4x< 2x + 1 ≤ 3x + 2
2006-06-27 11:32:54
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answer #5
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answered by Vivek 4
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take this 1st: 4x< 2x + 1
or 4x-2x< 1
0r x<1/2
now take anothe one
2x + 1 ≤ 3x + 2
or -x<1
or x>-1
hence -1
2x-3x<2-1
-x<-1
X > 1
2006-06-27 11:26:29 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I cannot believe you guys are doing his homework..... sheesh
2006-06-27 11:39:20 · answer #7 · answered by retard 2 · 0⤊ 0⤋
x=>-1
2016-03-27 06:15:23 · answer #8 · answered by Anonymous · 0⤊ 0⤋