I'm trying to become a horse jockey. The job application is asking for a BMI calculation, but I have no idea what this is! Can you please help me? I have always been the shortest guy around. As a kid, everyone told me I should pursue this. 65 years later I’m finally doing it. I can’t wait for my first race!
2006-06-27 09:35:59 · 36 answers · asked by Bent 5 in Entertainment & Music ➔ Polls & Surveys
I love how many people are taking this confession-by a 481 pound, 75-year old trying to break into the world of professional horse racing-seriously.
Whoever wrote this deserves a medal for illuminating the gullibility of Yahoo! users
2006-06-27 09:39:33 · answer #1 · answered by tye_dyedfan 3 · 0⤊ 1⤋
About 100
2006-06-27 09:37:10 · answer #2 · answered by Nelson_DeVon 7 · 0⤊ 0⤋
I think you are bsing. First of all, it would take you years to lose enough weight to become a horse jockey. They must be small as well as thin. And if you are older than 65 years old, time is precious and quite frankly you don't have enough of it to lose that much weight. Even if you weren't old, aren't you jumping the gun just a bit if you are already applying? I can't even imagine an employer handing you an application.
2006-06-27 09:40:49 · answer #3 · answered by outlawsister1973 3 · 0⤊ 0⤋
A 65 plus 487 lb horse jockey? You cant be serious.
2006-06-27 09:38:43 · answer #4 · answered by proffalken1975 4 · 0⤊ 0⤋
I can help you...
Ideally, the Gaussian kernel is K(s,t) = exp(-(s2 + t2)/(2C2))/(2*Pi*C2)
In polar coordinates s = r*cos(theta), t = r*sin(theta), this expression is K(r, theta) = exp(-r2/2C2)/(2*Pi*C2)
The value of C determines the effective range of K; points (s,t) beyond a distance of about 3*C barely contribute to K. K() is essentially flat beyond 3*C. The quartic approximation capitalizes on this. The only symmetric quartic polynomial equal to 1 at r=0, to 0 at r=3, and with derivative 0 at r=3 is q(r) = (1-(r/3)2)2
Therefore Spatial Analyst's "Gaussian" kernel is a multiple of K(r, theta) = (1-(r/3C)2)2 suitably normalized to have an area of 1. These values are very quick to calculate and so the density is quick to compute.
It appears your BMI is 1200 which is a good sign since that is exactly what secretariat weighed at the height of his career.
2006-06-27 13:30:33 · answer #5 · answered by ? 6 · 0⤊ 0⤋
This is a joke right. lets see Your short enough but are you light enough and man you got to be at least 75 now. Is the horse going to pull you in a reinforced buggy. At that height you must look like a 4' 8" diameter round ball of human. Impossible everyone. Nice joke dude.
2006-06-27 09:43:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I don't think you can be a horse jockey at 487 pounds, they are supposed to be really small. Google BMI calculator, and there are tons of sites. There's one on glamour.com too.
2006-06-27 09:37:25 · answer #7 · answered by Nonna 3 · 0⤊ 0⤋
dude you weigh 487 lbs... I'm 5'5" and I weigh bout 350 pounds less than you. The point is to be light so the horse doesn't have to carry extra baggage. They will NEVER let you in.
2006-06-27 09:38:02 · answer #8 · answered by Amers 2 · 0⤊ 0⤋
why are you trying to become a horse jockey when you weigh as much as the horse. lose about 375 pounds and you might be able to ride the horse.
2006-06-27 09:40:33 · answer #9 · answered by snuffy_muffy_eater 3 · 0⤊ 0⤋
Can't be a horse jockey unless you're like 85-110 sorry.
2006-06-27 09:38:08 · answer #10 · answered by Toodles 2 · 0⤊ 0⤋