You can rule out parabola and line immediately.
line has single power x and y only
parabola has single power y and x² only (or x and y² only)
So it's an ellipse or hyperbola.
An ellipse has the form (x-h)²/a² + (y-k)²/b²=c² [note that if a=b, the ellipse is a circle]
A hyperbola has the form (x-h)²/a² - (y-k)²/b² = c²
My guess therefore is ellipse.
2006-06-27 09:36:49
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answer #1
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answered by bequalming 5
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First I warn you to ABSOLUTELY DO NOT MEMORIZE ANY OF THE ABOVE that anyone has written. While it may be correct, memorization in math is like praying to Satan in a Christian church. It is forbidden.
First, look at the equation:
4x^2 + xy + 4y^2 - 8 = 0
Conceptual math would tell you that a line has no powers greater than one in the variables. Thus, a line is eliminated.
A hyperbola's x^2 and y^2 values must be negative. Why? A hyperbola's curves go in opposite directions. Thus, they must be different in terms of their value (positive vs. negative) A hyperbola is eliminated as 4x^2 and 4y^2 are both positive.
A parabola must have a y^2 or x^2 value. NOT BOTH. As a result, a parabola is eliminated.
As a result, only ellipse is left, and it is correct as both x^2 and y^2 terms are positive.
2006-06-27 17:54:59
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answer #2
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answered by Anonymous
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This is actually an ellipse that has been rotated. This is how you can tell. The general equation for a conic section (in two dimensional Cartesian coordinates) is:
Ax^2+Bxy+Cy^2+Dx+Ey+F=0
You need to use the discriminant B^2-4AC (in this case 1^2-4*4*4=-63).
If discriminant < 0, it's an ellipse.
If discriminant = 0, it's a parabola.
If discriminant > 0, it's a hyperbola.
D and E determine horizontal and vertical displacement, respectively, and B determines a rotation (as well as the conic type, as mentioned above). F pretty much determines the size of the thing.
2006-06-27 17:14:30
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answer #3
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answered by HCP 2
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This is an ellipse, since both of the x^2 and y^2
2006-06-27 16:37:42
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answer #4
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answered by Bit m 1
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this is equation of the form
ax^2 + by^2 +2gx +2fy + 2hxy + c =0
ok now listen,u just cant look at it and say wht is it ,unless u perform the following tests
first of all calculate this determinant
|a h g |
|h b f | = del
|g f c|
u can remember it as "all hot girls having boy friends go for cinema " lol
now u can test it out very easily
second step is to caluclate h^2 - ab
now ur job is done, look at the table and come to the conclusion
CASE 1
del !=0 (determinant is not equal to zero)
h^2-ab<0 Ellipse
h^2-ab=0 Parabola
h^2-ab>0 Hyperbola
CASE 2
del =0
h^2-ab<0 Point
h^2-ab=0 Pair of parallel or coincident lines, or an imaginary locus
h^2-ab>0 Pair of intersecting lines
CASE 3
if a=b and h=0 the conic is a circle
so now i hope u can selct which one of it is ;)
hope it helps
if u further need any help ,u can im me at escape_velocity009
thanks
2006-06-27 17:11:12
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answer #5
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answered by escape_ 1
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this is a circle since a and c, the coeffecients for x and y are equal, or it could be an ellipse since the x and y are both squared.
2006-06-27 16:42:30
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answer #6
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answered by Anonymous
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It is an ellipse.
Lines do not have exponents greater than 1, they can all be expressed as y=mx+b.
A parabola will only have one squared term, not both.
2006-06-27 16:35:42
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answer #7
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answered by -j. 7
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