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Determine the derivative of f(x) = x^2 In x^2

2006-06-27 08:31:37 · 5 answers · asked by good_but_naughty_gal 1 in Science & Mathematics Mathematics

5 answers

I'll lead you in the most important part, but it is up to you to complete it.

Derivative of x . y = x'.y + x.y'

Then, you will have:

f'(x) = (2x . ln x^2) + x^2 (ln x^2)'

Continue from here, the only problem that you may have is finding the derivative of ln y , which you can see in the link below.

2006-06-27 08:38:21 · answer #1 · answered by felizmino213 3 · 0 0

Remember the product rule for derivatives: (first times the derivative of the second) + (second times thederivative of the first). I say it, "first derivative of the second plus the second derivative of the first). Say it over and over until its second nature (that's what my math teacher had the class do).

Another key point to this problem is the derivative of ln x, which is (1/x). For example, what's the derivative of ln(x^2)? (This is important for the problem):

y = ln (x^2) (sample equation)

y' = [1/(x^2)](2x) (In words, the derivative of our sample equation is one over the argument times the derivative of the argument. In this case, the argument is (x^2) and the derivative of it is 2x)

y = 2/x (simplified - canceling an "x" from the top and bottom)

Now you have all the pieces to solve the problem.

Good luck!

2006-06-27 16:18:26 · answer #2 · answered by student2000 2 · 0 0

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2006-06-29 19:23:11 · answer #3 · answered by Anonymous · 0 0

Using the product rule:

2x*ln(x^2) + 1/(x^2)*(2x)*(x^2)

= 2x*ln(x^2) + 2x

OR 2x[ln(x^2) + 1]

2006-06-27 16:08:02 · answer #4 · answered by jenh42002 7 · 0 0

Use product rule for differentiation.

2006-06-27 16:04:16 · answer #5 · answered by J_humor 2 · 0 0

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