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Remeber that perpendicular lines have negative reciprocal slopes, so the slope of the line you are trying to find is 1/3 (that is the negative reciprocal of -3). You know that the y intercept is 5, remember that slope intercept form is y = mx + b where m is slope and b is y intercept. You know both of these things now, the m = 1/3 and the b = 5. Your equation is y = 1/3x + 5.

2006-06-27 06:39:18 · answer #1 · answered by houndgirl44 2 · 1 0

If the lines are perpendicular, their slopes are negative reciprocals of each other. So the slope of your first line is -3, so the perpendicular slope is 1/3.

You now know that if y = mx + b, and you know that b = 5, so the equation is y =1/3 x + 5.

2006-06-27 13:42:44 · answer #2 · answered by -j. 7 · 1 0

1) Find the slope of the known line:

y = -3x+1
Since it is in the form of y = mx+b and m is the slope,
the slope is -3.

2)Since the lines are perpendicular, the slope of the unknown line is the negative reicprocal of the slope of the known line:

The negative reciprocal of -3 = +1/3

3) Use the y = mx+b to write the desired equation
Slope = m = 1/3
y-intercept = b = 5

y = (1/3)x+5

2006-06-27 21:32:18 · answer #3 · answered by Anonymous · 1 0

y=x/3 + 5

2006-06-27 13:38:04 · answer #4 · answered by Pascal 7 · 1 0

y=1/3x+5

2006-06-27 13:38:08 · answer #5 · answered by amdirien 4 · 1 0

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