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4 answers

independed to your hub or switch that home many port have

2006-06-27 01:00:56 · answer #1 · answered by 942 5 · 1 1

The 1024 number is partly correct, it was the party line from IEEE. Some of us enginners were able to defeat this limitation as mixed topology's were added to networks. Such as locating ten-base-t routers within the network backbone. 1024 was a limitation number placed on a per segment basis.

Basically, the Star topology is based on schema similar to the ten-base-t topology. However it was still a ring network schema. Early versions used co-ax cable and barrel connectors. Then gradually twisted pair cabling replaced this. One star hub daisy chains to the other and so forth. Four computers on each hub. Each computer name having to be unique ID and so forth. Limitations on speed and traffic is the major constraint in the Star schema. Everyone talks, Everyone listens. Pass the Packet. Toss the Trash.The more more computers you place on the chain the slower the performance. A lot of excess traffic was the basic demise of this topology. However at the time it was a cheap networking solution.

The rule of thumb 20 years ago was no more than 20 computer in a segment , 5 hubs with 4 computers each star group. Additional network cards at the server recommended for each 20 computers or additional segment. So you can do the math from here. The maximum I ever saw in a production environment was 1065 computers/printers on a single server. Two separate segments. The server had additional room for more cards, however the server speed at the time, did not make adding more NIC's feasible And it was mostly a word processing and document storage system with printer distribution.

Hope this helps!

2006-06-27 01:41:16 · answer #2 · answered by Shuxs 3 · 0 0

A star topology supports up to 1024 computers on the LAN

They share bandwidth though.

http://www.techiwarehouse.com/cms/articles.php?cat=5

2006-06-27 01:10:45 · answer #3 · answered by ? 6 · 0 0

Five Computers...

I Guess...

2006-06-27 01:15:37 · answer #4 · answered by Web-designer © 5 · 0 0

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