What is the formula for a sphere in 3 Dimensional space?

Answer 1

THE CORRECT ANS IS

(x-a)^2+(y-b)^2+(z-c)^2=r^2

where (a, b, c) is the centre of the sphere
and 'r' is the radius
this gives only surface of the sphere
for its interior part '=' is replaced by '<'

Answer 2

The volume of a sphere formula is (4/3)(pi)(r)^3. But the surface area of a sphere is 4(pi)(r)^2.

Hope that helps. ;)

Answer 3

A spheresuface with radius r and center (a,b,c) is
(x-a)^2 + (y-b)^2 + (z-c)^2 = r^2.
When you need the inside of the sphere then
(x-a)^2 + (y-b)^2 + (z-c)^2 < r^2.
4/3 pi r^3 is its volume
4 pi r^2 is its area

Answer 4

Well, without telling what kind of formula you want, I will write the 2 most used.
1) (x - x0)^2 + (y - y0)^2 + (z - z0)^2 = R^2
is the formula that uses cartesian coordinates. A point P(x,y,z) is on the surface of a sphere centered in (x0, y0, z0), with a radius of R if and only if (x,y,z) verify the above equation;

2) the equations:
x = x0 + R * sin(theta) * cos (phi)
y = y0 + R * cos(theta) * cos(phi)
z = z0 + R * cos(theta)
where theta is in [0, pi] and phi is in (-pi, pi] are the polar coordinate equations for the surface of a sphere centered in (x0, y0, z0) with a radius of R.
By taking a value for theta, phi and a radius, the (x,y,z) point is on the surface of that sphere.

Answer 5

x^2+y^2+z^2=r^2

Answer 6

its simply 4/3 pi r^3

Answer 7

4/3 pi r^3