Solve the puzzle???

Question

A person climbs down 7 steps when he sees his professor starting to climb from the bottom of the stairs. They pass each other and moving down he finds that he has 4 more steps to go when his prof reached the top. Considering prof takes 2 steps to one step of the person, calculate no. of steps.

Answer 1

let total steps = x
Steps covered by person after Prof starts climbing from bottom = x - (7+4)
Bcoz already 7 steps over and 4 more steps remaining.
Steps covered by prof in the same time = x
Persons speed = s , Profs speed = 2s
x-(7+4)/s = x/2s.
x= 22 steps

Answer 2

Let the top of the stair case represent a total of x stairs, after the student climbs down he will have total of y + 4 stairs to go, so the total number of stairs is x = 7 + 4 + y, when the student climbs down the y stairs, the prof would have walked up 2y and reached the top, so 2y = x, thus solving the two eq => y = 11 and therefore x = 7 + 4 + 11 = 22

Answer 3

You can use the tried and true distance formula to solve this, d=r*t, where the student's and professor's distances travelled differ by 7+4=11. Thus, the professor travelled the entire distance in the time the student needed to travel the same distance minus 11, with the professor at twice the speed.

professor: d = 2 * t
student: d - 11 = 1 * t, or d = t + 11

Substituting d back to the professor's equation:

2 * t = t + 11
t = 11

So in the time involved, the student walked 11 steps, while the professor who walked twice as fast traversed 22 steps. Thus, the length of the staircaise is 22 steps.

(Of course, you can also solve for t originally and then substitute it. You still still end up with d=22 in the end.)

Answer 4

let the total no,of steps me = x
the person climed down 7 steps
his prof reaches to xth step when he has to climb down 4 steps more. prof takes 2 steps = 1 step of the person.

so,for the person to climb down x-7 steps is required when the prof starts .

when the person has completed x - 4,the prof reaches xth step.
so this means that 2(x-4) = x because the prof takes twice the no,of steps as the person does.
therefore,2x - 8 = x

mmmm.can u give a hint please, i don't know why but im not getting it :(

Answer 5

22

Answer 6

22

Answer 7

When he passes the prof, they may have been climbing for three years... how many steps did he take before passing the prof?

Answer 8

The professor is 11 (7+4) ssteps ahead of the person. and as he takes 2 steps to one step of the person so number of steps is 22.
At the 10th step they meet.

Answer 9

22 is the answer

steps covered by person is 7 plus 4 so 11

so lets take distance is x = 11

and steps covered by professor is we dont know

so it is x

and the time taken by person to climb is lets take s

and the time taken by the profesor is double than that of person,

that is 2s

so,.................

lets equate,
one equation is x = 11 and time = s
keep it as x - 11 = s

and professor's is x = 2s

solve both eqn

x - 11/x=s/2s
x - 11/x=1/2
2x - 22 = x
so x = 22.

Answer 10

your riddle is not clear enough. Does the student start climbing down when he sees the prof start going up or is he already on step 7 at that time? It may be taken either way. I would love to solve your riddle, but please rethink it