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A gas in a cylinder is held at a constant pressure of 2.2×10^5 Pa and is cooled and compressed from a volume of 1.79 m^3 to 1.30 m^3. The internal energy of the gas decreases by 1.37×10^5 J.
Find the work done by the gas.

Find the absolute value |Q| of the heat flow into or out of the gas.

2006-06-26 22:20:29 · 3 answers · asked by Sagely 4 in Science & Mathematics Physics

3 answers

work done 1.078 X 10^5
heat is -0.292X10^5

2006-06-26 22:24:28 · answer #1 · answered by The Game BOY ! 1 · 2 0

dQ=dW+dU

dW=pdV;p=2.2×10^5;dV=91.79-1.3)

dU=1.37×10^5

2006-06-27 05:26:33 · answer #2 · answered by robin 3 · 0 0

Do ur homework on ur own!

2006-06-27 05:24:07 · answer #3 · answered by ♥♥ ĎᵲέӚϻ_ῬѓїЍϚ€$Ṧ ♥♥ 4 · 0 0

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