4 years ago, Tony was 5 times as old as Sarah. 2 years from now, Tony will be twice as old as Sarah. How old are Tony and Sarah, now?
2006-06-26 19:49:19 · 5 answers · asked by slobberknocker_usa 7 in Education & Reference ➔ Words & Wordplay
let the age of tony be x and sarah be y
then,
four years ago,
(x-4)=5(y-4)
x-4=5y-20
x-5y= -16......................(1)
after two years,
(x+2)=2(y+2)
x+2=2y+4
x-2y=2..........................(2)
by subtracting eqn. (1) from (2),
x -2y=2
-x+5y=16
--------------------
3y=18
y=6
put value of y in eqn (2)
x-2*6=2
x=2+12
x=14
therefore, the age of tony and sarah now are 14 and 6 respectively.
2006-06-26 20:00:57 · answer #1 · answered by vandy 2 · 8⤊ 0⤋
Sarah is 6, Tony is 14.
Let T= Tony's age now
Let S= Sarah's age now
T-4 = 5(S-4)
T+2 = 2(S+2)
Solving the top equation for T we get T = 5S-16
Substitute 5S-16 for T in the second equation to get S=6.
Substitute 6 for S in any of the equations to get T=14.
2006-06-27 03:05:36 · answer #2 · answered by G.V. 6 · 0⤊ 0⤋
Sarah is Eight and two thirds years old, and Tony 23 1/3 years old.
2006-06-27 02:59:39 · answer #3 · answered by Jeff A 1 · 0⤊ 0⤋
Sarah is 6. Tony is 14.
I'm sorry that I took a little too long solving it out for you.
2006-06-27 03:08:57 · answer #4 · answered by G. Rex 3 · 0⤊ 0⤋
Sarah-6
Tony-14
Soln:
let the present age of tony be : t
let the present age of Sarah be :s
four years ago
t-4=5(s-4)
which implies that t=5s-16 ----eq.1
two years from now
t+2=2(s+2)
which implies that t+2=2s+4 -----------eq2
putting th value of t from eq1 in eq2
5s-16+2=2s+4
3s = 18
s=6-------------ans.
putting the value of s in eq1 to get the value of t
t-4=5(6-4)=10
t=14-----------ans.
2006-06-27 03:05:12 · answer #5 · answered by swami 2 · 0⤊ 0⤋