2006-06-26 15:55:49 · 9 answers · asked by cysreese 1 in Business & Finance ➔ Careers & Employment
3x – 8x^2 + 11 – 4x^2 + 2x – 1 – 8 + 3x^2
3x+2x = 5x
-8x^2-4x^2+3x^2 = -12x^2+3x^2 = -9x^2
11-1-8 = 2
-9x^2+5x+2
2006-06-26 15:58:46 · answer #1 · answered by kinsey_ad 2 · 0⤊ 0⤋
if x stands for a hidden value
3x-8x2+11-4x2+2x-1-8+3x2
(3x+2x)+(8x^2-4x^2+3x^2)= 11-1-8
5x+7x^2= 3
if x stands for a mult sing
3x-8x2+11-4x2+2x-1-8+3x2
3x+2x=(-8x2)+(4x2)-1-8+(3x2)+11
5x = 8-1-8+6+11
5x=16
x=3.2
i really bealive is the first one cause x stands for a hidden value in most ecuations
if you need any other help contact me
2006-06-26 23:43:07 · answer #2 · answered by yaniris b 1 · 0⤊ 0⤋
5x-16 i think im sorta confused by what are x's and what are multiplication signs...if u want to do it yourself just do all the multiplication first...so if im right in knowing what is x's and what is multiplication the next step should be 3x-16+11-8+2x-1-8+6...then you just add the x's and you get 5x and you add all the numbers together and get -16 so the answer is 5x-16 unless you mean that whenever ti says x2 that is like x to the second power...im totally confused now...if x2 means x to the second power then the answer is -9x2+5x+2
2006-06-26 22:59:45 · answer #3 · answered by shark7777 3 · 0⤊ 0⤋
Wait, you're letting a bunch of internet idiots do your homework for you? That's so depressing...
2006-06-26 22:58:54 · answer #4 · answered by dreth 3 · 0⤊ 0⤋
-9x2+5x+2
2006-06-26 23:02:03 · answer #5 · answered by chikeymonky 2 · 0⤊ 0⤋
and apparently at least 1 person is wrong :P
2006-06-26 23:00:18 · answer #6 · answered by gets flamed 5 · 0⤊ 0⤋
its too confusing. what is the x and a multiplication sign?
2006-06-26 23:05:47 · answer #7 · answered by Al Gene A 1 · 0⤊ 0⤋
learn how to do this, don't cheat!!! it's very simple algebra
2006-06-26 22:58:04 · answer #8 · answered by BM0027 3 · 0⤊ 0⤋
12344567891011121314151617181920212223242526272829303132333435363738394041424344454647484950!!!!!
2006-06-26 22:59:17 · answer #9 · answered by {0-0} 2 · 0⤊ 0⤋